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Re: M06-04 [#permalink]
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hi
statement 1 is sufficient as mentioned in earlier replies.
as for stat 2.. g^2+2g−3<0
(g+3)(g-1)<0 so g can be -2,-1,0, or 1.....
when we substitute -2 or 0 ans is -1..... however -1 and 1 will give us 1 as anything raised to power 0 is 1... A shud be the ans
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Re: M06-04 [#permalink]
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Bull78 wrote:
Guys please correct me if I am wrong

g^4-1 = g^4/g = g^3 therefore we are concerned about the value of g^3, as if it yields an even number the answer will become 1

1.- g^2 < 1 There is no other number rised to the power of two that yields a negative result, so g = 0, sufficient

2.- x= -1 or x = 3, as each of the results is odd, it is sufficient to realize that the value of g is -1.

So answer is still D

it is (g^4)-1 and not g^(4-1)
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Re: M06-04 [#permalink]
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Correct question with a solution is below:

If \(g\) is an integer what is the value of \((-1)^{g^4 - 1}\) ?

(1) \(g^2<{1}\) --> since \(g\) is an integer then \(g=0\). Sufficient to calculate the value of \((-1)^{g^4 - 1}\).

(2) \(g^2+2g=0\) --> \(g(g+2)=0\) --> \(g=0\) or \(g=-2\). Since both possible values of \(g\) are even then \((-1)^{even^4 - 1}=(-1)^{even-1}=(-1)^{odd}=-1\). Sufficient.

Answer: D.

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