Guys please correct me if I am wrong
g^4-1 = g^4/g = g^3 therefore we are concerned about the value of g^3, as if it yields an even number the answer will become 1
1.- g^2 < 1 There is no other number rised to the power of two that yields a negative result, so g = 0, sufficient
2.- x= -1 or x = 3, as each of the results is odd, it is sufficient to realize that the value of g is -1.
So answer is still D
it is (g^4)-1 and not g^(4-1)