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m06 Q20

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Joined: 16 Nov 2010
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Location: United States (IN)
Concentration: Strategy, Technology
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m06 Q20 [#permalink]

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12 Apr 2011, 02:56
Hi

For this question, I calculated as follows :

5^(root(2)) * 5^(root(2))

= 5^(2root(2))

= 25(root(2))

Is the above approach correct ? Also, where can I learn more about such tricky exponent stuff ?

Regards,
Subhash
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Joined: 20 Dec 2010
Posts: 2022
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Kudos [?]: 1415 [1] , given: 376

Re: m06 Q20 [#permalink]

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12 Apr 2011, 03:09
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subhashghosh wrote:
Hi

For this question, I calculated as follows :

5^(root(2)) * 5^(root(2))

= 5^(2root(2))

= 25(root(2))

Is the above approach correct ? Also, where can I learn more about such tricky exponent stuff ?

Regards,
Subhash

Yes, the approach is correct.

$$(5^{\sqrt{2}})^2=(5^{2})^{\sqrt{2}}=25^{\sqrt{2}}$$ [Note: $$(x^m)^n=x^{mn}=(x^n)^m$$]

I think GMAT Club Math book exponents in number theory did a decent job.
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WE 1: Business Development
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Re: m06 Q20 [#permalink]

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13 Apr 2011, 10:48
yea, i would be happy to find that kind of practice if someone have it.

thanks.
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Joined: 01 Feb 2011
Posts: 758
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Kudos [?]: 90 [0], given: 42

Re: m06 Q20 [#permalink]

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15 Apr 2011, 15:47
Looks alright to me.

I got 25^(sqrt(2)) too.

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Re: m06 Q20   [#permalink] 15 Apr 2011, 15:47
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