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M06 Q9

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Author Message
Intern
Intern
Joined: 22 May 2013
Posts: 45
Concentration: General Management, Technology
GPA: 3.9
WE: Information Technology (Computer Software)
Followers: 0

Kudos [?]: 8 [0], given: 7

GMAT ToolKit User
Re: M06 Q9 [#permalink] New post 03 Jun 2013, 04:51
ramgmat wrote:
Hi all,
I tried solving it using the formulas of matrices using the formula \frac{1}{2}[x1 (y2-y3) + x2( y3-y1) + x3(y1-y2)] and got the answer as 4. Took the values for x1, x2, x3 and y1, y2, y3 as the values of the three co-ordinates of the vertices.

Can you please tell me where am I making a mistake?


May be you did some calculation mistake perhaps?
I applied the formula 1/2 * (5 (5-3) + 3 * (3-1) + 1 * (1-5))

=1/2 * (10+6-4)
=6

Hence, D

PS: Like my approach? Help me with some Kudos. 8-)
_________________

PS: Like my approach? Please Help me with some Kudos. :-)

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Re: M06 Q9   [#permalink] 03 Jun 2013, 04:51
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M06 Q9

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