M09 #07 : GMAT Club Tests

M09 #07

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Senior Manager

Joined: 29 Jul 2009

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M09 #07 [#permalink]

07 Oct 2009, 06:11

Hi everyone, I read the explanation for this question but I'm not convinced how if the angle ABC is 90, then we can conclude that a^2=\frac{1}{a}

According to me if the angle ABC is 90, then the triangle becomes isosceles but the sides are a^2 and \frac{2}{a}. Because is a triangle rectangle (\frac{2}{a})^2 = (a^2)^2 + (a^2)^2 ---> 2 = a^6

Can anyone explain why my reasoning is wrong?
Thank you

CIO

Joined: 02 Oct 2007

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Re: M09 #07 [#permalink]

07 Oct 2009, 06:43

Here's the discussion you need to have a look at:
ds-triangle-m09q07-72173.html

You can search for the questions you need to ask a question of in this thread:
gmat-club-tests-master-threads-all-tests-78599.html

We try to avoid posting the duplicate threads. Thank you for cooperation

.
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Senior Manager

Joined: 29 Jul 2009

Posts: 316

Followers: 4

Kudos [?]: 157 [0], given: 9

Re: M09 #07 [#permalink]

07 Oct 2009, 07:45

I'm sorry I tried to look for that thread but couldn't find it. The normal search does not work properly, and I cannot access to the other thread you post. I'll avoid duplicating threads next time. sorry for the inconvenience.

CIO

Joined: 02 Oct 2007

Posts: 1260

Followers: 75

Kudos [?]: 506 [0], given: 334

Re: M09 #07 [#permalink]

07 Oct 2009, 08:03

Sorry, there was a typo. You must be able to access both threads now.

mikeCoolBoy wrote:

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Re: M09 #07 [#permalink] 07 Oct 2009, 08:03

		Similar topics	Author	Replies	Last post
Similar Topics:	8	m09 q22	CrushTheGMAT	38	07 Sep 2008, 13:18
	13	DS : TRIANGLE (m09q07)	amitdgr	39	29 Oct 2008, 00:53
	9	M09 #20	ritula	20	10 Nov 2008, 03:24
		m09 #34	ritula	6	10 Nov 2008, 04:10

M09 #07

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