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Re: M09#12 [#permalink] New post 14 Jun 2013, 06:56
is it not as simple as 0.9/1.2?
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Re: M09#12 [#permalink] New post 15 Jun 2013, 03:36
santas wrote:
is it not as simple as 0.9/1.2?

No. We shouldn't consider like that. We cannot simply add 0.1 for every cylinder. Actually we need to do add 10% of the sum.
Consider Power of one cylinder engine is 1. For every cylinder increase, power increases by 10%. So then

2 Cylinder Engine power = 1+(10% of 1) = 1.1
3 Cylinder Engine power = 1.1+(10% of 1.1) = 1.21
4 Cylinder Engine power = 1.21+(10% of 1.21) = 1.33
5 Cylinder Engine power = 1.33+(10% of 1.33) = 1.46
6 Cylinder Engine power = 1.46+(10% of 1.46) = 1.61
7 Cylinder Engine power = 1.61+(10% of 1.61) = 1.77
8 Cylinder Engine power = 1.77+(10% of 1.77) = 1.95
9 Cylinder Engine power = 1.95+(10% of 1.95) = 2.15
10 Cylinder Engine power = 2.15+(10% of 2.15) = 2.37
11 Cylinder Engine power = 2.37+(10% of 2.37) = 2.61
12 Cylinder Engine power = 2.61+(10% of 2.61) = 2.87

So \frac{2.15}{2.87}=0.75

Hope this helps !
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Re: M09#12 [#permalink] New post 15 Jun 2013, 03:38
very simple...

each time a cylinder is added it increases by 1.1

So the required ans is
= (1.1)^9/(1.1)^12

= 1/(1.1)^3

= 1000/11*11*11

= 1000/1331(lol more simpler)

= 0.75 ...which is D
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Re: M09#12 [#permalink] New post 16 Jun 2013, 05:09
The answer is obviously D
Ratio= (1/1.333)=3/4=0.75
Re: M09#12   [#permalink] 16 Jun 2013, 05:09
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