m09 Q 18

For DS problem I always group the answer choices and work my way through by eliminating them till I get to the correct one.
I keep options A&D together and options BCE together and separate them by a "/" . it looks something like "AD / BCE". Then I go to the statements.
Now consider: (case I)
If statement 1 is sufficient
Then there are only two possibilities either only statement 1 is sufficient and 2 is not which gives you answer "A", or statement 2 is also sufficient that means both of them are sufficient which gives you answer choice "D". So keep them & cancel the other three option BCE. you are left with AD / BCE, you can straight way eliminate BCE. Consider the answer options, "B" = only 2, is wrong since 1 is already giving you the answer, "C" = combined, wrong, since 1 is already giving you the answer, "E" = not sufficient, since 1 is already giving you the answer.

Now that you are left with only 2 options A & D and the problem becomes bit simpler. You need only to check whether 2 is also sufficient. If 2 is then cancel out A & go for "D". Otherwise stick to A.
(case II)
If statement 1 is not sufficient
Then you can cancel out A&D and write AD / BCE. now check for statement 2 and see whether it gives you an answer. If it does then B is the answer, if it does not then you have to check by combining. If that also fails then the answer is E.
I am just applying POE (process of elimination ) at the beginning to simplify my task and work with fewer answer choices.
Hope the explanation is clear. Its a bit lengthy but I could not manage to keep it more simple.