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M1 q19 error?

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Intern

Joined: 09 Nov 2009

Posts: 24

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M1 q19 error? [#permalink]

15 Nov 2009, 10:30

I think this is an error. If we plug in x < 1 and x >1 we get to different results if y =1. Stem does not state M is an interger. Am I off?

CIO

Joined: 02 Oct 2007

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Re: M1 q19 error? [#permalink]

16 Nov 2009, 01:12

I'm sorry, I don't follow how you arrived to this conclusion. Where did you plug the values of X in?
If we take S1, we get this:
\sqrt{X} \gt \sqrt{Y}
or
X \gt Y
after we square both sides. Why would you plug in X \lt 1 and Y =1 in there if it says that X \gt Y? S1 is sufficient to answer the question.
Let's see what we have with S2:
X^2 \gt Y^2
I see no reason to plug X \lt 1 and Y=1 in here... S2 is not sufficient since plugging in X=4, Y=2 and X=-4, Y=2 produce different results while not violating S2.

I hope this helps.

ajonas wrote:

I think this is an error. If we plug in x < 1 and x >1 we get to different results if y =1. Stem does not state M is an interger. Am I off?

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Re: M1 q19 error? [#permalink] 16 Nov 2009, 01:12

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M1 q19 error?

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