posting the entire problem again.
To arrive at its destination on time the bus should have maintained a speed of V kmh throughout the journey. Instead, after going the first third of the distance at V kmh, the bus increased its speed and went the rest of the distance at (1.2)*V kmh. As a result, the bus arrived at its destination X minutes earlier than planned. What was the actual duration of the trip?
1. V = 60
2. X = 20
Solution is B - but how is S2 sufficient if i still have 2 variables and 2 unknowns in the equation?
can somebody please help? thanks in advance!
as per the question s/v is what we need to find, i.e the duration of the trip, so it is enough to find s/v , no need to find separately s and v.