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(998/1002) * 0,02 = 19.96/20.04 which is 9.98 /10.02 The numbers that we add in both parts are 4.97/5.03 which is equal to 9.94/10.06

It is certain that we can not reach the ratio 1, because you increase upper part less than below part .So it is imposible to reach the ratio 1. In order to reach 1 you have to increase upper part more than below part. The ratio between than have to be [(19.96/20.04),(4.97/5.03)]

In general it is certain that (a+b)/(c+d) , the ratio will be between [a/c , b/d] and will be closer the ratio which's number are bigger.

Which of the following is closest to \frac{(998*0.02 + 4.97)}{(1002*0.02 + 5.03)} ?

A. 0.50 B. 0.89 C. 0.98 D. 1.02 E. 1.05

Notice that the numerator is slightly less than the denominator: \frac{(998*0.02 + 4.97)}{(1002*0.02 + 5.03)}\approx{\frac{20+4.97}{20+5.03}}, thus the fraction will be less, but very close to 1.

The answer is C. After increasing the numerator i.e (1000*0.02 + 5) and decreasing the denominator i.e (1000*0.02 + 5), the resulting fraction is 1. Thus the answer should be 0.98. _________________

Which of the following is closest to \frac{(998*0.02 + 4.97)}{(1002*0.02 + 5.03)} ?

(C) 2008 GMAT Club - m10#22

* 0.50 * 0.89 * 0.98 * 1.02 * 1.05

The OE is not clear..i did it without rounding it off and not getting the answer:(

Let’s use some logic..

By observation, numerator is very close too denominator.

D/E are out as numerator cannot be > denominator. A is also out because numerator is substantially > 1/2(denominator). B is equivalent to 90% i.e. numerator < 90% (denominator) where as .

{(998 x 0.02) + 4.97}/{(1002 x 0.02) + 5.03} can approximately be written as {(1000 x 0.02) + 5}/{(1000 x 0.02) + 5} keeping in mind that we increased the numerator overall and decreased the denominator overall, thereby increasing the value of the fraction.

However, after having done so, the value of the fraction becomes 1. We know the original fraction is close to 1. We have two options 1.02 and 0.98. We also know that while rewriting the fraction, we increased its value from the original, therefore the original has to be less than 1. So, I go with C.