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I think you have to consider the defeated matches for the second equation, even though it does not affect the final result.
I set this up in two equations:
1) 3W + D = 31 To minimize the number of wins, then we need to maximize the number of points via draw. Total points add up to the remaining 31 points to make it to 40 incremental to the 9 obtained after 5 games.
2) W + D = 15 Total number of wins + draws should add up to the 15 games to make 20 games on top of the 5 games already played
If the team wins 6 times, to get the maximum points, they should get 20-5-6 draws = 9 draws and it gets 9 + 6*3 + (20-5-6)*1 = 36 points <40 pts -> A is wrong If it wins 7 times, if the gets 10 draws and loses 3 times the team will reach the 40 points at the end --> Answer is B = 7
The Team has currently scored 9 points in 5 matches , so in the remaining 15 matches it is needs to score 31 points with the condition ( Least number of matches to win ) . For example If it has 14 Draws + 1 Win = 14 + 3 = 17 score (REJECTED) If it has 13 Draws + 2 Wins = 13 + 3*2 = 19 score (REJECTED)
We can formulate D + 3 * W = 31 ( where D = draws , W = wins ) This equation is only satisfied when D = 7 , W = 8
7 ( Draws )* 1 + 3 * 8 ( wins ) = 31 .
Hence least number of wins to obtain a score of 40 in 20 matches is : 8