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# M10:Q5 - DS

Author Message
Intern
Status: Active
Joined: 30 Jun 2012
Posts: 37
Location: India
Followers: 5

Kudos [?]: 81 [0], given: 36

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25 Dec 2012, 05:42
Bunuel,

Please point out where I am going wrong.

Area of rectangle/sqaure (assumption: TV is either rectangle or square) = $$\frac{d^2}{2}$$ where d = diagonal.

So, doesn't question itself suffice, in this case?
_________________

Thanks and Regards!

P.S. +Kudos Please! in case you like my post.

Intern
Status: Active
Joined: 30 Jun 2012
Posts: 37
Location: India
Followers: 5

Kudos [?]: 81 [0], given: 36

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25 Dec 2012, 05:46
Bunuel,

Please point out where I am going wrong. May be I am getting confused here..

Area of rectangle/sqaure (assumption: TV is either rectangle or square) = $$\frac{d^2}{2}$$ where d = diagonal.

So, doesn't question itself suffice, in this case?
_________________

Thanks and Regards!

P.S. +Kudos Please! in case you like my post.

Intern
Joined: 06 Jun 2012
Posts: 7
GMAT Date: 10-16-2013
WE: Project Management (Health Care)
Followers: 0

Kudos [?]: 0 [0], given: 1

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07 Jan 2013, 01:45
"In two similar triangles (or rectangles), the ratio of their areas is the square of the ratio of their sides." - Can you explain how can this be derived with simple proof?
Math Expert
Joined: 02 Sep 2009
Posts: 35932
Followers: 6858

Kudos [?]: 90082 [0], given: 10413

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07 Jan 2013, 03:55
Bunuel,

Please point out where I am going wrong.

Area of rectangle/sqaure (assumption: TV is either rectangle or square) = $$\frac{d^2}{2}$$t where d = diagonal.

So, doesn't question itself suffice, in this case?

Area of rectangle does not equal to $$\frac{d^2}{2}$$.
_________________
Re: M10:Q5 - DS   [#permalink] 07 Jan 2013, 03:55

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# M10:Q5 - DS

Moderator: Bunuel

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