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# M12 Q32

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06 Jun 2014, 09:42
sunita123 wrote:
Hi Bunuel,
I have a question here,
so when you considered both the statement and got x^3*y^4 = 5^3*2^4=2000.
i want to know how you reached there? did you try plugging in x=1 ,2, 3 , 4 and 5 and y =1 , 2 etc?just trying to understand the thought process . when i tried to take both the statements i could not do that .

Bunuel wrote:
echizen wrote:
If $$x^3*y^4 = 2000$$, what is $$y$$?

1. $$x$$ is an integer
2. $$y$$ is an integer

[Reveal] Spoiler: OA
E

Source: GMAT Club Tests - hardest GMAT questions

If $$x^3*y^4 = 2000$$, what is $$y$$?

(1) $$x$$ is an integer.
(2) $$y$$ is an integer.

Each statement alone is insufficient. When considering together we have: $$x^3*y^4 = 5^3*2^4=2000$$, but since $$y$$ is in even power it can be 2 as well as -2. Not sufficient.

Do you mean how I got 5^3*2^4? I made prime factorization of 2,000:

$$2,000 = 16*125 = 2^4*5^3$$.

Hope it's clear.
_________________
Re: M12 Q32   [#permalink] 06 Jun 2014, 09:42

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# M12 Q32

Moderator: Bunuel

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