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M12 Q32

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Re: M12 Q32 [#permalink] New post 06 Jun 2014, 09:42
Expert's post
sunita123 wrote:
Hi Bunuel,
I have a question here,
so when you considered both the statement and got x^3*y^4 = 5^3*2^4=2000.
i want to know how you reached there? did you try plugging in x=1 ,2, 3 , 4 and 5 and y =1 , 2 etc?just trying to understand the thought process . when i tried to take both the statements i could not do that .


Bunuel wrote:
echizen wrote:
If x^3*y^4 = 2000, what is y?

1. x is an integer
2. y is an integer

[Reveal] Spoiler: OA
E

Source: GMAT Club Tests - hardest GMAT questions


If x^3*y^4 = 2000, what is y?

(1) x is an integer.
(2) y is an integer.

Each statement alone is insufficient. When considering together we have: x^3*y^4 = 5^3*2^4=2000, but since y is in even power it can be 2 as well as -2. Not sufficient.

Answer: E.


Do you mean how I got 5^3*2^4? I made prime factorization of 2,000:

2,000 = 16*125 = 2^4*5^3.

Hope it's clear.
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Re: M12 Q32   [#permalink] 06 Jun 2014, 09:42
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