Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 30 Aug 2016, 13:46

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# M14 #5

Author Message
Forum Moderator
Status: mission completed!
Joined: 02 Jul 2009
Posts: 1426
GPA: 3.77
Followers: 181

Kudos [?]: 797 [1] , given: 621

### Show Tags

04 Nov 2010, 11:57
1
KUDOS
If set consists of even number of integers, is the median of set negative?

Exactly half of all elements of set are positive.
The largest negative element of set is -1.

[Reveal] Spoiler:
С

I found the most efficient way to solve this question.

Is is asked whether the median is negative? for sufficiency we have to demonstrate one Yes and one No.

lets say that in S are 4 numbers, $$A1, A2, A3, A4$$. and median is equal to $$(A2+A3)/2$$ - for this to be negative, absolute value of A2 must be grater than A3. |A2|>|A3|. you need to check whether it |A2|>|A3| is always true or false.

1)Exactly half of all elements of set are positive.
Remember here that 0 is neither positive nor negative.
For insuficiency we need to find this |A2|>|A3| to be true and false.
True |A2|>|A3|, S {-2;-2;1;2}, |-2|>|1|
False |A2|>|A3|, S {-2;0;1;2}, |0|<|1|

2)The largest negative element of set is -1.
True |A2|>|A3|, {-2;-1;0;0} |-1|>|0|
False |A2|>|A3, false {-2;-1;3;4} , |-1|<|3|

1)&2) two positive elements and the largest negative integer is -1
so {-3;-1;1;2}, because the second number must be -1 and the smallest postitive out of two is 1, thus (-1+1)/2=0 - which is not negative , for other cases when third element is grater than 1, answer is NO, not negative (-1+4)/2=positive.
_________________

Audaces fortuna juvat!

GMAT Club Premium Membership - big benefits and savings

Math Expert
Joined: 02 Sep 2009
Posts: 34511
Followers: 6302

Kudos [?]: 79970 [0], given: 10022

### Show Tags

04 Nov 2010, 19:33
Pkit wrote:
If set consists of even number of integers, is the median of set negative?

Exactly half of all elements of set are positive.
The largest negative element of set is -1.

[Reveal] Spoiler:
С

I found the most efficient way to solve this question.

Is is asked whether the median is negative? for sufficiency we have to demonstrate one Yes and one No.

lets say that in S are 4 numbers, $$A1, A2, A3, A4$$. and median is equal to $$(A2+A3)/2$$ - for this to be negative, absolute value of A2 must be grater than A3. |A2|>|A3|. you need to check whether it |A2|>|A3| is always true or false.

1)Exactly half of all elements of set are positive.
Remember here that 0 is neither positive nor negative.
For insuficiency we need to find this |A2|>|A3| to be true and false.
True |A2|>|A3|, S {-2;-2;1;2}, |-2|>|1|
False |A2|>|A3|, S {-2;0;1;2}, |0|<|1|

2)The largest negative element of set is -1.
True |A2|>|A3|, {-2;-1;0;0} |-1|>|0|
False |A2|>|A3, false {-2;-1;3;4} , |-1|<|3|

1)&2) two positive elements and the largest negative integer is -1
so {-3;-1;1;2}, because the second number must be -1 and the smallest postitive out of two is 1, thus (-1+1)/2=0 - which is not negative , for other cases when third element is grater than 1, answer is NO, not negative (-1+4)/2=positive.

Also discussed here: ds-set-14343.html
_________________
Re: M14 #5   [#permalink] 04 Nov 2010, 19:33
Similar topics Replies Last post
Similar
Topics:
m14 q5 3 06 Dec 2009, 06:36
20 M14 #19 19 02 Feb 2009, 22:06
5 M14 #18 19 02 Feb 2009, 21:55
6 M14 #27 19 13 Nov 2008, 17:55
18 M14 #13 25 11 Nov 2008, 21:40
Display posts from previous: Sort by

# M14 #5

Moderator: Bunuel

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.