sset009 wrote:

If a certain soccer game ended 3:2, what is the probability that the side that lost scored first?

(Assume that all scoring scenarios are equiprobable)

(C) 2008 GMAT Club - m14#29

* \(\frac{1}{4}\)

* \(\frac{3}{10}\)

* \(\frac{2}{5}\)

* \(\frac{5}{12}\)

* \(\frac{1}{2}\)

2 teams A and B ... A won and B lost..

the problems is similar where we have 5 slots, A can take 3 and B can take 2 postions

all possible combinations = 5!/(2! * 3!) = 10

fav cambinations we know that first slot is B.. so rest slots are 4 and A can take 3 postions and B can take 1

= 4! / (3! * 1!) = 4

Probability = 4/10 = 2/5 option C

But when you say that fav cambinations we know that first slot is B.. so rest slots are 4 and A can take 3 postions and B can take 1