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How many of the first 100 terms of this sequence are less than 0.891?

A-7 B-8 C-9 D-10 E-12

I got this question wrong by considering and counting 0 as a term, yielding 0% as one of the terms below 0.891. I'm sure this is obvious to most, but how is one to know that 0 isnt a term when interpreting the question?

Re: M14 Q3 - Why isn't 0 "a term" [#permalink]
13 Oct 2009, 04:59

dpgxxx wrote:

A sequence is defined as follows:

An = n/n+1

How many of the first 100 terms of this sequence are less than 0.891?

A-7 B-8 C-9 D-10 E-12

I got this question wrong by considering and counting 0 as a term, yielding 0% as one of the terms below 0.891. I'm sure this is obvious to most, but how is one to know that 0 isnt a term when interpreting the question?

Can someone help here as to why "0" cannot be considered The question doesnt say anything about "n", to be considered as natural or whole number or integers..

Re: M14 Q3 - Why isn't 0 "a term" [#permalink]
13 Oct 2009, 06:21

We should probably state that the first element of the sequence is \(\frac{1}{2}\). However, I thought it goes without saying that the first element is found by plugging "1", the second one by plugging "2" and so on. There's no zero element of a sequence, it starts with the first element. Anyone else thinks we should specify the first element of the sequence? _________________

Re: M14 Q3 - Why isn't 0 "a term" [#permalink]
13 Oct 2009, 09:26

chetan2u wrote:

u r right .. we always start a series with 1.. as also seen while calculating sum of first n nos etc

do we not consider the series here as sum of 1st n NATURAL numbers? wherein the first number is 1 whereas the above series doesnt mention anything specific

Re: M14 Q3 - Why isn't 0 "a term" [#permalink]
13 Oct 2009, 09:32

dzyubam wrote:

We should probably state that the first element of the sequence is \(\frac{1}{2}\). However, I thought it goes without saying that the first element is found by plugging "1", the second one by plugging "2" and so on. There's no zero element of a sequence, it starts with the first element. Anyone else thinks we should specify the first element of the sequence?

really sorry but still not able to get it ...as per my understanding until and unless it is not mentioned specifically we can consider any number which fits the equation....that goes without saying that we can consider -ve number,fraction as well.

Kindly explain what is meant by zero element? is it meaning A0 is the zero element and cannot be considered?

Re: M14 Q3 - Why isn't 0 "a term" [#permalink]
13 Oct 2009, 10:21

looks like the question is not fully correct, it misses one of the premises to specify a range for n.

first element will be the one where n has the least value as specified by the n's range of allowable values; for eg., if it was specified that n is an integer always greater than -5 then first element is -4/-3 = 4/3 (where n= -4) _________________

Thanks, Sri ------------------------------- keep uppp...ing the tempo...

Press +1 Kudos, if you think my post gave u a tiny tip