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# M15 #3

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Math Expert
Joined: 02 Sep 2009
Posts: 27170
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Kudos [?]: 40967 [0], given: 5576

Re: M15 #3 [#permalink]  05 Feb 2012, 06:29
Expert's post
akhilright wrote:
Thanks Bunuel,
I understood that particular reply, but fundamentaly i did not get how has the reply reworded A (n+1)=An/n+1, from the real equation given in the question

First of all, if you look at the formula given in the initial post and the one given in mine, you'll notice that they're basically the same: just replaced n with n+1. Next, I didn't reworded the question, I changed it so that it would be more GMAT type.
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Verbal Forum Moderator
Status: Preparing for the another shot...!
Joined: 03 Feb 2011
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Location: India
Concentration: Finance, Marketing
GPA: 3.75
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Kudos [?]: 770 [0], given: 62

Re: M15 #3 [#permalink]  07 Jan 2013, 05:13
Expert's post
Bunuel.
Since its given that n>1, then how can we even deal with A1.
This is why I got this one wrong.
Chose A, which is wrong.
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Re: M15 #3 [#permalink]  07 Jan 2013, 05:27
Expert's post
Sorry for being dumb.
But then why we deal with even $$A$$1. For all n>1, the series must start with $$A$$2?
Regards.
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Re: M15 #3 [#permalink]  07 Jan 2013, 05:52
Expert's post
Marcab wrote:
Sorry for being dumb.
But then why we deal with even $$A$$1. For all n>1, the series must start with $$A$$2?
Regards.

The sequence starts with A1, naturally. But we have formula that gives the terms starting from A2. It's a common way of defining sequences, for example check these questions from MGMAT:
sequence-s-is-defined-as-sn-sn-1-1-1-sn-1-1-for-all-n-144382.html
sn-2sn-1-4-and-qn-4qn-1-8-for-all-n-1-if-s5-q4-125965.html

More questions on sequences to practice:
search.php?search_id=tag&tag_id=112 (PS)
search.php?search_id=tag&tag_id=111(DS)
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Kudos [?]: 770 [0], given: 62

Re: M15 #3 [#permalink]  07 Jan 2013, 06:13
Expert's post
In fact I did such questions but it was not mentioned that n>1. Thats why there was no problem in doing questions where even finding other values was not at all confusing.
But I am unable to recover from the shock that this question gave.
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Re: M15 #3 [#permalink]  04 Feb 2013, 16:39
I was a bit confused on what the question is asking. I thought it was asking n could be a lot of number, and how many of those n could equal to 1/2...
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Re: M15 #3 [#permalink]  20 Apr 2014, 07:21
Elements of this series gradually get smaller when n increases. Knowing 1 element would let us calculate the others, so definitely we will know how many is smaller than 1/2
1) is sufficient. 2) lets us to know the value of A2, so also sufficient.

Choose d
Re: M15 #3   [#permalink] 20 Apr 2014, 07:21

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# M15 #3

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