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M15#18

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Intern
Intern
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Status: VRAM
Joined: 07 Feb 2014
Posts: 5
Location: India
Concentration: Finance, Marketing
GMAT Date: 09-06-2014
WE: Consulting (Computer Software)
Followers: 0

Kudos [?]: 6 [0], given: 1

Re: M15#18 [#permalink] New post 25 Feb 2014, 03:21
Hi GMATians ,

its pretty simple

question gives 3 B,3R,3G balls =9 balls

so selection of each is 3C1 and selection of any 3 balls is 9C3

therefore

3C1*3C1*3C1/9C3 or (3C1)^3/9C3=9/28

VR
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Joined: 20 Oct 2013
Posts: 77
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Kudos [?]: 7 [0], given: 13

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Re: M15#18 [#permalink] New post 27 Apr 2014, 00:18
Probability (3 marbles of 3 colors) = (3C1)^3/9C3=27/84=9/28 => d
Intern
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Status: Anyone from chandigarh preparing for GMAT . Kindly buzz me or leave a message.
Joined: 12 Jan 2014
Posts: 12
Location: India
GPA: 3.65
WE: Information Technology (Computer Software)
Followers: 0

Kudos [?]: 0 [0], given: 236

GMAT ToolKit User
Re: M15#18 [#permalink] New post 06 Jul 2014, 10:29
3C1*3C1*3C1/9C3 = 9/28 .Hope its right
Re: M15#18   [#permalink] 06 Jul 2014, 10:29
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M15#18

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