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Intern
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Set S is composed of consecutive multiples of 3. Set T is composed of consecutive multiples of 6. If each set contains more than one element, is the median of set S larger than the median of set T?
s1) The least element in either set is 6.
s2) Set T contains twice as many elements as set S.
(C) 2008 GMAT Club - m15#27
Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
EACH statement ALONE is sufficient
Statements (1) and (2) TOGETHER are NOT sufficient
Statement (1) by itself is insufficient. If set contains many more elements than set , its median can be greater than that of set .
Statement (2) by itself is insufficient. We don't know how the sets are positioned against each other.
Statements (1) and (2) combined are sufficient. The answer is "no".
The correct answer is C.
my question is...cant this still be proved ineffective?
it says consecutive multiples of 3 or 6, but you cannot just assume they start with small elements
to TEST C:
eg. S= (3,6,9,12,15,18) median = 10.5, T = (6,12,18) median = 12
median S < median T = therefore NO
BUT there is no restriction on where these consecutive multiples start:
what if S = (102,105,108, 111, 114, 117) median = 109.5 , T = (6, 12, 18) median = 12
so shouldnt the answer be E?
am i missing something here? thanks in advance..
Last edited by viperm5 on 08 Aug 2009, 16:18, edited 1 time in total.
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Manager
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Please post the exact question i.e. mention the set names in the following statements:
"is the median of set larger than the median of set"
"Set contains twice as many elements as set "
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Intern
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Aleehsgonji wrote: Please post the exact question i.e. mention the set names in the following statements:
"is the median of set larger than the median of set"
"Set contains twice as many elements as set " ooops sorry didnt realize i missed those. thanks!! fixed.
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Manager
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Each statement alone is insufficient.
Combining 1 and 2
Both the sets S & T start with 6.
From 2, number of elements in T is twice as the number of elements in S.
S = {6,9,12}
T = {6,12,18,24, 30,36}
Median of S = 9
Median of T = 21
1 and 2 are sufficient. Answer is C.
Though median of S is less than median of T, we are able to arrive at this answer using both the statements.
In data sufficiency, we should not look for Yes or No answer but we should for arriving at the solution.
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Intern
Joined: 09 Feb 2009
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Aleehsgonji wrote: Each statement alone is insufficient.
Combining 1 and 2
Both the sets S & T start with 6.
From 2, number of elements in T is twice as the number of elements in S.
S = {6,9,12}
T = {6,12,18,24, 30,36}
Median of S = 9
Median of T = 21
1 and 2 are sufficient. Answer is C.
Though median of S is less than median of T, we are able to arrive at this answer using both the statements.
In data sufficiency, we should not look for Yes or No answer but we should for arriving at the solution. ahh makes sense now. thanks for clarification!! 
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