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# M16 Q18

Author Message
CEO
Status: Nothing comes easy: neither do I want.
Joined: 12 Oct 2009
Posts: 2797
Location: Malaysia
Concentration: Technology, Entrepreneurship
Schools: ISB '15 (M)
GMAT 1: 670 Q49 V31
GMAT 2: 710 Q50 V35
Followers: 218

Kudos [?]: 1448 [1] , given: 235

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04 Apr 2010, 13:49
1
KUDOS
I think the ans should be E, as y =0 and x as odd integer case is not considered.

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670-to-710-a-long-journey-without-destination-still-happy-141642.html

CEO
Status: Nothing comes easy: neither do I want.
Joined: 12 Oct 2009
Posts: 2797
Location: Malaysia
Concentration: Technology, Entrepreneurship
Schools: ISB '15 (M)
GMAT 1: 670 Q49 V31
GMAT 2: 710 Q50 V35
Followers: 218

Kudos [?]: 1448 [0], given: 235

### Show Tags

05 Apr 2010, 14:06
Bump.... BB could u pls check this.
_________________

Fight for your dreams :For all those who fear from Verbal- lets give it a fight

Money Saved is the Money Earned

Jo Bole So Nihaal , Sat Shri Akaal

GMAT Club Premium Membership - big benefits and savings

Gmat test review :
670-to-710-a-long-journey-without-destination-still-happy-141642.html

Math Expert
Joined: 02 Sep 2009
Posts: 33525
Followers: 5937

Kudos [?]: 73612 [0], given: 9903

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05 Apr 2010, 17:24
Expert's post
gurpreetsingh wrote:
I think the ans should be E, as y =0 and x as odd integer case is not considered.

In case $$x=odd$$ and $$y=0$$ --> $$2*x*5*y=0=even$$

Question: $$2*x*5*y=even$$. As there is 2 as a multiple, then this expression will be even if $$5xy=integer$$. Basically we are asked is $$5xy=integer$$ true?

Note that $$x$$ and $$y$$ may not be integers for $$2*x*5*y$$ to be even (example $$x=\frac{7}{9}$$ and $$y=\frac{9}{7}$$) BUT if they are integers then $$2*x*5*y$$ is even.

(1) $$2+x+5+y=even$$ --> $$7+x+y=even$$ --> $$x+y=odd$$. Not sufficient. (x=1 and y=2 answer YES BUT x=1.3 and y=1.7 answer NO)

(2) $$x-y=odd$$. Not sufficient. (x=1 and y=2 answer YES BUT x=1.3 and y=0.3 answer NO)

(1)+(2) Sum (1) and (2) $$(x+y)+(x-y)=odd_1+odd_2$$ --> $$2x=even$$ --> $$x=integer$$ --> $$y=integer$$ --> Both $$x$$ and $$y$$ are integers. Hence sufficient.

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Re: M16 Q18   [#permalink] 05 Apr 2010, 17:24
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# M16 Q18

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