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M16 Q35 PS from GMAT club tests [#permalink]
14 Aug 2008, 09:25
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Question Stats:
47% (02:35) correct
52% (02:05) wrong based on 71 sessions
X , A , and B are positive integers. When X is divided by A , the remainder is B . If when X is divided by B , the remainder is A - 2 , which of the following must be true? (A) A is even (B) X + B is divisible by A(C) X - 1 is divisible by A(D) B = A - 1(E) A + 2 = B + 1Source: GMAT Club Tests - hardest GMAT questions REVISED VERSION OF THIS QUESTION IS HERE: m16-q35-ps-from-gmat-club-tests-68861.html#p1220163
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Re: PS from GMAT club test M16 Q35 [#permalink]
14 Aug 2008, 09:42
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durgesh79 wrote: spent 10 minutes on this one .... and finally guessed it and it was right ... X, A, and B are positive integers. When X is divided by A, the remainder is B. When X is divided by B, the remainder is A-2 . Which of the following must be true? A is even X+B is divisible by A X-1 is divisible by A B = A-1 A+2 = B+1 D guessing.. From X / A = p * A + B X/B = Q* B + (A-2) So.. B < A and (A-2) < B So B < A < B+2 Since A and b ARE INTEGERS A should be B+1 So I vote for D spent more than 3 Mins
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Re: PS from GMAT club test M16 Q35 [#permalink]
14 Aug 2008, 09:53
you never define p for this: Quote: X / A = p * A + B to be true, p must be negative. that doesn't make any sense. \frac{x}{A} = Ap + Bx = pA^2 + ABTake x = 9, a = 7 \frac{9}{7} = 7p + 99 = 49p + 63-54 = 49p-\frac{54}{49} = pDo you mean this: \frac{x}{a} = \frac{x-b}{a} + \frac{b}{a}
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Re: PS from GMAT club test M16 Q35 [#permalink]
14 Aug 2008, 09:58
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durgesh79 wrote: spent 10 minutes on this one .... and finally guessed it and it was right ... X, A, and B are positive integers. When X is divided by A, the remainder is B. When X is divided by B, the remainder is A-2 . Which of the following must be true? A is even X+B is divisible by A X-1 is divisible by A B = A-1 A+2 = B+1 D firm: When X is divided by A, the remainder is B. -- means A>B (remainder always less A) e.g. 5/10 -- remainder -- 5 25/10 -- remainder - 5 ( B<A) When X is divided by B, the remainder is A-2 that means B>A-2 --> B+2>A Combine both equations. B+2>A>B (A, B are positive intergers.. there is only one values posible between B and B+2.. that is B+1 so A=B+1
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Last edited by x2suresh on 14 Aug 2008, 10:01, edited 1 time in total.
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Re: PS from GMAT club test M16 Q35 [#permalink]
14 Aug 2008, 10:01
chan4312 wrote: durgesh79 wrote: D guessing..
From X / A = p * A + B X/B = Q* B + (A-2)
spent more than 3 Mins Above equations are incorrect. X = p * A + B X = Q* B + (A-2)
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Re: M16 Q35 PS from GMAT club tests [#permalink]
27 Apr 2010, 23:07
Also from substitution method it we can see that by taking numbers for A and B , taking 3 and 2 the closer number would be 5, as the conditions get satisfied so we can assure that 3 and 2 are A,B. Thus satisfies the conditions.
Took 2 min
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Re: M16 Q35 PS from GMAT club tests [#permalink]
28 Apr 2011, 10:20
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spent more than 10 min trying to solve, finally substituted numbers (A=3, B=2) to arrive at (D) ... great approach by x2suresh ... divisor>remainder ... life can be so simple
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Re: M16 Q35 PS from GMAT club tests [#permalink]
28 Apr 2011, 15:57
D.
Plugging in numbers and backsolving - Solving from the last option.
X=5;A=3;B=2 -> We can eliminate all the answer choices except D. <1 Min
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Re: M16 Q35 PS from GMAT club tests [#permalink]
30 Jun 2011, 01:33
I know this is a dumb question- but I cant solve these 2 inequalities mathematically : b < a a-2 <b
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Re: M16 Q35 PS from GMAT club tests [#permalink]
02 May 2012, 11:29
Excellent Concept Problem: D is correct answer.
When X is divided by A, the remainder is B. => A > B When X is divided by B, the remainder is (A-2). => B > A - 2 Combining the two inequalities: A > B > A - 2 i.e.: B is between A and (A-2), so B must be equal to A-1. B = A - 1. (D) is the correct answer.
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Re: M16 Q35 PS from GMAT club tests [#permalink]
03 May 2013, 05:18
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durgesh79 wrote: X , A , and B are positive integers. When X is divided by A , the remainder is B . If when X is divided by B , the remainder is A - 2 , which of the following must be true? (A) A is even (B) X + B is divisible by A(C) X - 1 is divisible by A(D) B = A - 1(E) A + 2 = B + 1Source: GMAT Club Tests - hardest GMAT questions spent 10 minutes on this one .... and finally guessed it and it was right ...  BELOW IS REVISED VERSION OF THIS QUESTION:If x, a, and b are positive integers such that when x is divided by a, the remainder is b and when x is divided by b, the remainder is a-2, then which of the following must be true?A. a is even B. x+b is divisible by aC. x-1 is divisible by aD. b=a-1E. a+2=b+1When x is divided by a, the remainder is b --> x=aq+b --> remainder=b<a=divisor (remainder must be less than divisor); When x is divided by b, the remainder is a-2 --> x=bp+(a-2) --> remainder=(a-2)<b=divisor. So we have that: a-2<b<a, as a and b are integers, then it must be true that b=a-1 (there is only one integer between a-2 and a, which is a-1 and we are told that this integer is b, hence b=a-1). Answer: D.
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Re: PS from GMAT club test M16 Q35 [#permalink]
05 May 2013, 13:47
x2suresh wrote: X / A = p * A + B X/B = Q* B + (A-2)
Above equations are incorrect.
X = p * A + B X = Q* B + (A-2)
took me almost 10 minutes to accept that the first 2 equations are really incorrect. But it helps to substitude numbers.
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Re: PS from GMAT club test M16 Q35 [#permalink]
09 May 2013, 18:01
Ultimor wrote: x2suresh wrote: X / A = p * A + B X/B = Q* B + (A-2)
Above equations are incorrect.
X = p * A + B X = Q* B + (A-2)
took me almost 10 minutes to accept that the first 2 equations are really incorrect. But it helps to substitude numbers.  Agreed. It's a good trap, one that testmakers know people fall into, easily.  [old way of thinking & bad habits!!!]
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Re: M16 Q35 PS from GMAT club tests [#permalink]
11 May 2013, 07:27
Simple Plugin type Question :-
X = 11 A = 3 B = 2 ...........................
Substitute in answer choices and you will find that only D satisfies the condition. Solved in under 1:30 min.
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Re: M16 Q35 PS from GMAT club tests
[#permalink]
11 May 2013, 07:27
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