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m18 08 [#permalink] New post 07 Sep 2010, 18:19
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i'm not sure how to solve this problem.

If neither [m]x[/m] nor [m]y[/m] is 0, what is [m]\frac{2x + y}{x - 2y}[/m] ?

1. [m]\frac{x}{x + y} = 2[/m]
2. [m]x - 2y = 4[/m]
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Re: m18 08 [#permalink] New post 07 Sep 2010, 18:35
woodahy wrote:
i'm not sure how to solve this problem.

If neither x nor y is 0, what is \frac{2x + y}{x - 2y} ?

1. \frac{x}{x + y} = 2
2. x - 2y = 4


(1) \frac{x}{x + y} = 2 --> x=2x+2y --> x=-2y --> \frac{2x + y}{x - 2y}=\frac{-4y+y}{-2y-2y}=\frac{-3y}{-4y}=\frac{3}{4}. Sufficient.

(2) x - 2y = 4 --> x=2y+4 --> \frac{2x + y}{x - 2y}=\frac{2y+4+y}{4}=\frac{3y+4}{4} --> we don't know the value of y, hence we can not calculate numerical value of this fraction. Not sufficient.

Answer: A.
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Re: m18 08 [#permalink] New post 07 Sep 2010, 18:52
Thanks. Much better than explanation given. I had 3y/4y and didn't realize I had the answer

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Re: m18 08   [#permalink] 07 Sep 2010, 18:52
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