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Intern
Joined: 09 Sep 2010
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0% (00:00) correct
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Team A, team B, team C, and team D take part in a tournament in which every team plays once with each of its opponents. 3 points are awarded for victory, 1 for a draw, and 0 for defeat. The scoring table currently is as follows:
team B 7 points
team C 4 points
team A 0 points
team D 0 points
How many games are yet to be played in the tournament?
0
1
2
3
it cannot be determined from the information given
Team B has played all of its three matches - it could not have accumulated 7 points in 2 games. Also, because team A and team D have no points, team B tied with team C. Therefore team C beat either team A or team D. In either case, two games are yet to be played: A-D and D-C (or A-C).
The correct answer is C.
MY ISSUE :
Clearly the total no. of games is 3! i.e. 6 games
Then the total no. of points is 11 :-
Matches Pts Total
2 3 6 - Won (team B)
1 3 1 - Draw (team B)
1 3 3 -Won (team C)
1 1 1 - Draw (Team C)
So total no. of matches played : 5
Thus, 6 games to be played (-) 5 games played = 1 game remaining.
How come 2 matches remaining? Where am I wrong, pls help !!!
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Senior Manager
Joined: 30 Aug 2009
Posts: 296
Location: India
Concentration: General Management
Followers: 2
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sandhyash wrote: Team A, team B, team C, and team D take part in a tournament in which every team plays once with each of its opponents. 3 points are awarded for victory, 1 for a draw, and 0 for defeat. The scoring table currently is as follows:
team B 7 points
team C 4 points
team A 0 points
team D 0 points
How many games are yet to be played in the tournament?
0
1
2
3
it cannot be determined from the information given
Team B has played all of its three matches - it could not have accumulated 7 points in 2 games. Also, because team A and team D have no points, team B tied with team C. Therefore team C beat either team A or team D. In either case, two games are yet to be played: A-D and D-C (or A-C).
The correct answer is C.
MY ISSUE :
Clearly the total no. of games is 3! i.e. 6 games
Then the total no. of points is 11 :-
Matches Pts Total
2 3 6 - Won (team B)
1 3 1 - Draw (team B)
1 3 3 -Won (team C)
1 1 1 - Draw (Team C)
So total no. of matches played : 5
Thus, 6 games to be played (-) 5 games played = 1 game remaining.
How come 2 matches remaining? Where am I wrong, pls help !!! B played 3 games (2 win and 1 draw) and C played 2 games ( 1 win and 1 draw) the drawn game is b/w B and C so matches left are b/w A and D and b/w C and A or D
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Retired Moderator
Joined: 02 Sep 2010
Posts: 815
Location: London
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sandhyash wrote: Team A, team B, team C, and team D take part in a tournament in which every team plays once with each of its opponents. 3 points are awarded for victory, 1 for a draw, and 0 for defeat. The scoring table currently is as follows:
team B 7 points
team C 4 points
team A 0 points
team D 0 points
How many games are yet to be played in the tournament?
0
1
2
3
it cannot be determined from the information given
Team B has played all of its three matches - it could not have accumulated 7 points in 2 games. Also, because team A and team D have no points, team B tied with team C. Therefore team C beat either team A or team D. In either case, two games are yet to be played: A-D and D-C (or A-C).
The correct answer is C.
MY ISSUE :
Clearly the total no. of games is 3! i.e. 6 games
Then the total no. of points is 11 :-
Matches Pts Total
2 3 6 - Won (team B)
1 3 1 - Draw (team B)
1 3 3 -Won (team C)
1 1 1 - Draw (Team C)
So total no. of matches played : 5
Thus, 6 games to be played (-) 5 games played = 1 game remaining.
How come 2 matches remaining? Where am I wrong, pls help !!! There is only 1 draw. In a draw both teams get 1 point You are double counting that
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Intern
Joined: 09 Sep 2010
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Oh !!! I really was double counting the "Draw" match. Thanks a lot !!
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Status: Preparing for the another shot...!
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Bunuel. What should be the average time to be spent on this question. On the practice test, I took 3 minutes plus got it wrong.  After careful reviewing, I understood this one. Do these types actually appear on the real thing? Regards.
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Manager
Joined: 18 Oct 2011
Posts: 80
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Concentration: Entrepreneurship, Marketing
GMAT Date: 01-30-2013
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Pretty Straight forward..
If B has 7 points and C has 4 points and A & D have 0 points then B and C each played a draw game. That leaves 2 wins for B and 1 win for C to add up their total. Since there are 6 total games possible 6-4 = 2 games left to play.
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