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# m19 30

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Intern
Joined: 02 Jul 2010
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07 Sep 2010, 19:50
If $$x = 10^{10}$$ , $$\frac{x^2 + 2x + 7}{3x^2 - 10x + 200}$$ is closest to:

* $$\frac{1}{6}$$
* $$\frac{1}{3}$$
* $$\frac{2}{5}$$
* $$\frac{1}{2}$$
* $$\frac{2}{3}$$
can someone help me find an easy way to answer this one
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08 Sep 2010, 05:28
Since x is too large, so x^2 would be even larger, hence you can roughly calculate the fraction as
x^2/3x^2 = 1/3.
just discard the 'x' part and the constant part, as they are too insignificant compared to 'x^2'.

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08 Sep 2010, 15:26
woodahy wrote:
If $$x = 10^{10}$$ , $$\frac{x^2 + 2x + 7}{3x^2 - 10x + 200}$$ is closest to:

* $$\frac{1}{6}$$
* $$\frac{1}{3}$$
* $$\frac{2}{5}$$
* $$\frac{1}{2}$$
* $$\frac{2}{3}$$
can someone help me find an easy way to answer this one

yeah basically it is like a "spit in the ocean" where the smaller numbers dont matter at all. so you have this huge 10^20 on top with 3*10^20 on bottom so 1/3
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Re: m19 30   [#permalink] 08 Sep 2010, 15:26
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# m19 30

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