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Question Stats:
54% (01:24) correct
45% (00:30) wrong based on 2 sessions
f(x) = \frac{x}{x + 1} . What is f(\frac{1}{x}) in terms of f(x) ? (A) f(x)(B) -f(x)(C) \frac{1}{f(x)}(D) 1 - f(x)(E) none of the above Source: GMAT Club Tests - hardest GMAT questions
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CEO
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topmbaseeker wrote: f(x) = \frac{x}{x + 1} . What is f(\frac{1}{x}) in terms of f(x) ?
(C) 2008 GMAT Club - m19#14
* f(x)
* -f(x)
* \frac{1}{f(x)}
* 1 - f(x)
* none of the above f(\frac{1}{x}) = \frac{x}{x + 1}f(\frac{1}{x}) = f(x)A.
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Intern
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the answer is surely D. without a doubt. (1/x) / (1+1/x) = 1/x+1 
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f(1/x) = (1/x)/[(1+x)/x] = 1/(1+x)
D. 1 - f(x) = (x+1-x)/(x+1) = 1/(1+x)
So, Answer is D.
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Manager
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GMAT TIGER, your mistake is that f(1/x) = 1/(1+x) not x/(1+x)
Answer is D as shown by above explanations.
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Intern
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f(1/x)=1/(x+1)=(x+1-x)/(x+1)=1 - x/(x+1) = 1- f(x).
D.
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Senior Manager
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D.. without any doubt.
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cvinod wrote: f(1/x) = (1/x)/[(1+x)/x] = 1/(1+x)
D. 1 - f(x) = (x+1-x)/(x+1) = 1/(1+x)
So, Answer is D. Is there easy anyway to get from 1/x+1? I had to do the mateh for answer c and d to verfiy the answer. This took to long.
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Can someone please tell me how they got the answer to this question? I got an answer of D, but spent about 5 minutes manipulating the fractions of C and D.
Thanks!
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f(1/x) = (1/x)/(1/x+1)
f(1/x) = (1/x)/((x+1)/x)
f(1/x) = (1/x)(x/(x+1))
f(1/x) = 1/(x+1)
Just by looking at the answer choices, we can immediately eliminate all but D. Solve for D to eliminate E.
1-f(x) = 1 -x/(x+1)
1-f(x) = 1 -x/(x+1)
1-f(x) = x+1-x/(x+1)
1-f(x) = 1/(x+1)
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Senior Manager
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I reached till \frac{1}{(1+x)} thats alright.. But how did you guys know you had to subtract this value from 1 to get the answer in terms of f(x)?
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Can anyone explain this step by step....i don't get any of the explanations above. Thanks
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@aks1985
so f(x)= x/x+1. it is asking what f(1/x) is in terms of f(x).
So to find that you plug 1/x in for x in f(x). the result is,
(1/x)/[(1/x)+1]
since you have two fractions you will want to multiply by a reciprocal, but before that lets simply the denominator.
denominator= [(1/x)+1] you can simplify that by adding them together to create one term but to do that the denominators must be the same, so you end up with [(1/x)+(x/x)].
*note that (x/x)=1
now your equation for f(1/x) looks like (1/x)/[(1+x)/x]
multiply by the reciprocal so (1/x)*(x/1+x), the x in the denominator of 1/x cancels out with the x in the numerator of x/(1+x) and you end up with 1/(1+x)
now you have to find out what that equals in terms of f(x).
A) cant be because it is not the same equation of f(x)
B) This is not the cause because it is not -(x/(x+1))
C) Hold off on this one because a little algebra needs to be down
D)1-f(x)= 1- (x/x+1) which equals ((x+1)/(x+1))-(1/(x+1))---->x/(x+1) which is f(x)
So the answer is D
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Senior Manager
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Hi guys. For Algebra questions, I think the easiest way is plug-in. Clearly see f(1/x) = (1/x) / ((1/x) +1) = 1/(x+1). Don't take time to convert 1/(x+1) to a formula in terms of f(x), just examine each answer. Ans A: f(x) = x/(x+1) wrong Ans B: -f(x) = -x/(x+1) Wrong Ans C: 1/f(x) = (x+1)/x Wrong Ans D: 1 - f(x) = 1 - x/(x+1) = 1/(x+1) CORRECT
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f(x) = x / (x+1)
=> f(1/x) = (1/x) / ((1/x) + 1) = 1/(x+1)
now 1-f(1/x) = 1- [1 / (x+1)] = x / (x+1) = f(x)
So, we have f(x) = 1 - f(1/x)
or f(1/x) = 1 - f(x)
Hence D is the answer.
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topmbaseeker wrote: f(x) = \frac{x}{x + 1} . What is f(\frac{1}{x}) in terms of f(x) ? (A) f(x)(B) -f(x)(C) \frac{1}{f(x)}(D) 1 - f(x)(E) none of the above Source: GMAT Club Tests - hardest GMAT questions The best way to solve these kind of questions is to assume values... For example take x=2...with this value of x you will get f(x) as 2/3... Now find f(1/x) i.e. f(1/2), which will come out to be 1/3.... Now check which option satisfies the above relation...the only option that satisfies is D
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