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Re: m20 #13 [#permalink]
Did anyone try to use the VIC (Variable In Choice) method? I got the same result for A as I did for D.

I Used the following values:
Original Price of House = 100
X = 10
Y = 10

Now, we can calculate M:
M= 100*(11/10)*(9/10)

M= 99



A) 100 * [(99 / 11) / 9] = 100 * [99/99] = 100

D) [ 10,000(99) / (100+10) ] / (100 - 10) = [ 10,000(99) / 90 * 110 ] = [ 10,000(99) / (9*10) * (11*10) ] = [ 10,000(99) / (9*11) * (10*10) ] = [ 10,000(99) / (99) * (100) ] = 100
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Re: m20 #13 [#permalink]
Bump

I'm also having trouble trying to understand the solution.

I used M=1500; x=50; y=50. this gives a 1998 selling price of 2000 (2000*0.5*1.5=1500=M). If i use these values and plug them into both B and D i get the same result. wheres my mistake? :?

cheers
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Re: m20 #13 [#permalink]
Expert Reply
damamikus wrote:
Bump

I'm also having trouble trying to understand the solution.

I used M=1500; x=50; y=50. this gives a 1998 selling price of 2000 (2000*0.5*1.5=1500=M). If i use these values and plug them into both B and D i get the same result. wheres my mistake? :?

cheers


Note that for plug-in method it might happen that for some particular number(s) more than one option may give "correct" answer. In this case just pick some other numbers and check again these "correct" options only.

Hope it helps.

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