In both the cases, x=0
hence D
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Hi thanks for answering this Q
The OA is A
And this is the OE
The median of a five-element set is necessarily a member of this set. No other member of the given set but x can be 0. S2 is not sufficient. x can be 2 or 0.

I could not get my head around to why the second statement was insufficient, I guess the median for an odd number of elements in a set must be a member ofthe set. And if x/2 is the median, then x/2 must be an integer, so x must either be 0 or 2. However the question stem does not state that x is an integer!

Thanks

OA is A.

Median for set of odd numbers must be middle number in the sorted order.
Thus 0 means x or -x is middle number which implies x=0.

However St2 is never possible.

-Jvaidya

St2 alone will never be able to decide the value for x as it can be both 2 or 0 which is not true. However, St1 can give you 1 value i.e. x=0 which is correct.

Why are we no longer dealing with a set if we pick "A" ? The value of x is the only thing that's in question. The numbers of the set do not change.

I would say, at least on GMAT-Land, until and unless it's explicitly mentioned that set contains distinct objects..DO not take it for granted. In many question, you fill find the concept of same elements in a given set..!!

Stmt 1. The median of set (x, 1, -1, 3, -x) is 0

There are 5 no in the set and only x and -x are unknown. So x must be zero.



Stmt 2. The median of set (x, 1, -1, 3, -x) is \frac{x}{2}
x is variable here.

Answer is A
_________________

Cheers,
SD

My explanation is not going to be very different from others, but let me give it a shot. Please let me know if something is not clear.

Median of elements of any set arranged in ascending order will be the middle term if the number(count) of elements is odd.
Median of elements of any set arranged in ascending order will be the average of two middle terms if the number(count) of elements is even.

e.g.
A={-2,45,-56,0,23,-9,34}
Let's find the median of A:
Count= 7(Odd)
Arrange elements in ascending order:
A={-56,-9,-2,0,23,34,45}
Median is the middle term(because Count=7(odd)), i.e. {(Count+1)/2}th term.
Here, count=7; median will be (7+1)/2 i.e. 4th term.
4th term = 0 and is the median of the set.

One point worth noticing is that if the set has odd number of elements, Median must be one of its element. Like we saw, that "0" was one of the elements in the set.

case II:
B={-2,45,-56,0,23,-9,34,1}
Let's find the median of B:
Count= 8(Even)
Arrange elements in ascending order:
A={-56,-9,-2,0,1,23,34,45}
Median is the average of middle terms(because Count=8(Even)), i.e. Average of (Count/2)th term and ((Count/2)+1)th term.
Here, count=8; Count/2=4th term=0; And Count/2+1=4+1=5th term=1
Median = (0+1)/2 = 0.5
Thus, we saw that in case of even number of elements, median may be something other than any of the elements. Here 0.5 was not among the elements.

Coming to the question:

1.
Median of the set {x,1,-1,3,-x} is 0.
Count=5(Odd). Thus, we know that median must be one of the elements.
1 != 0
-1 != 0
3 != 0
Only, x or -x can be 0
x=0
Or
-x=0 i.e. x=0
We know for sure that x=0
Sufficient.

2.
Median of {x,1,-1,3,-x} is x/2.
Count=5(Odd)

Means; x/2 must be one among 1,-1,3,x or -x for we know that median of odd number of elements must be one of the elements itself.

Let's check one by one;
Say; Median = x
Means; x/2=x; It is possible only for x=0. If x=0
{x,1,-1,3,-x} becomes {-1,0,0,1,3}. Median=0, which is true.
So; x could be "0". But, we must try the same thing for other numbers as well.

Say; Median=1
i.e. x/2=1; x=2;
{x,1,-1,3,-x} becomes {-2,-1,1,3,2}. Median=1, which is true.
What we saw here that; x could be 2 as well.
If we made x=2; the median becomes 1, which is x/2; supporting the statement.

We already have two possible values of x; 0 and 2. We can stop here.
Not Sufficient.

Ans: "A"

Note: We could have also checked for other numbers:
Say; Median = 3
x/2=3
x=6
{x,1,-1,3,-x} becomes {-6,-1,1,3,6}. Median=1, which is false.
x/2=6/2=3; According to the statement, Median should be 3, but we got our median as 1. Thus, x can't be 6.

Say; Median = -1
x/2=-1
x=-2
{x,1,-1,3,-x} becomes {-2,-1,1,2,3}. Median=1, which is false.
x/2=-2/2=-1; According to the statement, Median should be -1, but we got our median as 1. Thus, x can't be -2.

Say; Median = -x
-x/2=-x, which is x/2=x. Same as first
x can be 0.
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from 1. x has to be zero to satisfy the given condition
from 2. x may be 0 or 2.
hence 1 alone is sufficient to answer the question.
my take option A

What is the value of x?

Note that the median of a set with odd number of elements is just the middle element, when arranged in ascending/descending order.

(1) The median of set \{x, -1, 1, 3, -x\} is 0. The median of this set of 5 (odd) elements must be the middle term, hence x=0. Sufficient.

(2) The median of set \{x, -1, 1, 3, -x\} is \frac{x}{2}. It could be that x=0 (in this case the set is {-1, 0, 0, 1, 3}) as well as it could be that x=2 (in this case the set is {-2, -1, 1, 2, 3}). Not sufficient.

Answer: A.
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