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A basket contains cards bearing numbers 10, 11,... , 20. If a card is drawn from the basket and is not returned to it, and then the second card is drawn from the basket, what is the probability that the first card drawn will have a prime number on it while the second will not?
This is my approach: Prob of prime number = 4/11 Prob of no prime on second card = 6/10
Total probability = 4/11 * 6/10 = 12/55
Please let me know if I am wrong. The answer choices are: 28/110 4/15 5/16 27/80 32/55