6 male and 8 female employees work in the IT department. If an expert group has to be formed including 2 men and 1 woman, how many variants are possible?
Please help explain the concept.. I am having a hard time understanding formulas of permutations and combinations.
3 step process:
1.) you need to SELECT 2 males out of 6. use 6C2 = 15
2.) then 1 female out of 8. 8C1=8
3.) number of ways to select 2 males AND 1 female = 15x8 (use multiplication when you see 'and' & use addition when you see 'or')
where is/was the gap in understanding? (the third step?)
ok this seems easy.. 6C2 = (6 * 5 )/(2*1) .. but the explanation given in GC CAT expands 6C2 in a different way . All good now. Thanks mate!