pkmme wrote:

I went through the explanation; however, I am a bit confused with the answer.

What is the maximum number of 4x4x4 cubes that can fit in a rectangular box measuring 10x12x16 ?

12

18

20

24

30

The 12x16 floor can be covered with 12 cubes. Another 12 cubes will form the second layer. The height of this construction will be 8; the box won't accommodate any more cubes.

The correct answer is D.

The volume of the n cubes and the box should be same.

so, n*4^3= 10.12.16 =>n = 30.

I dont understand why the base is taken as 12.16 in the explanation. This is not mentioned in the question. We can take the base as 10.16, thus the number of cubes = 10. The height is 12, so, the total number of cubes =30.

Let me know in case I am missing something.

I think we shud have all the dimensions of the rectangle , perfectly divisible by 4. If they are not , then we have to leave some place in the rectangle.

as 10 is not divisible by 4, the next best would be 8.

hence its 8*12*16/4^3 = 24.