I am a bit confused about this question.
If Ay + B = C and A, B and C are known, then there should be only one value of y = (C-B)/A.
1) C>B This should be sufficient because A, B and C are known. Correct? If C = 5, B = 4, A = 2, I will get a unique value of 'y'.
2) A>1 => Again,...All three variables are known. Hence, Sufficient.
I am really not able to follow the OE about #1 - Consider A= 0 and A=1..Why? A,B and C are known...I am lost.
Can you please help me?
This question is removed from the set. So, I wouldn't worry about it.
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