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If A, B, and C are known, then as long as C>B, A and y could only be one number. the trick is that A,B, and C are all known, if A was unknown then the answer would be infinite. For Example, 4y + 2 = 3, A=4 y=1/4 B=2 C=3, A B and C are known and C>B, so y is an easy calculation.

unless I am misinterpreting it, A is already known, so its value being more than one shouldnt matter.

"How many different numbers y" requires a definite answer in GMAT. It should be for instance 2,3 or any other number. It cannot be "can be determined" vs "cannot be determined"

All the explanations above make sense, but this question seems to me as non-standard as far as GMAT is concerned _________________

from statement 1 ; C>B , it doesn't make any sense , as it doesn't affect the value of y.

statement 2; A>0, this condition should exist since A can't be zero.

so, we can answer this question using statement 2. the Ans is B.

but this question asks about the different values of y. and, by using both these statement together or alone we cant say how many values does y have. hence, if we look from this perspective, the answer will be E.

plz tell the OA and source of question. _________________

kudos me if you like my post.

Attitude determine everything. all the best and God bless you.

If A, B and C are known the only case where y will have an unknown number of values is when A = 0 because there will be infinite possibilities. So, B correctly pinpoints that aspect.

I agree that B give answer, but question is asking for a specific number of Y values right? with Statement 2 we can say that we can find the value of y. but here we get multiples with different values of A B and C right????

Please correct me if if am wrong.... _________________

S1 is not sufficient. Consider \(A = 0\) (the answer is 0) and \(A = 1\) (the answer is 1).

S2 is sufficient. Because \(A \gt 1\) , \(A \gt 0\) and the only \(y\) that satisfies the condition is \(\frac{C - B}{A}\) . The correct answer is B.

Is the explanation for statement 2 correct? Why couldn't y = 0 and some other number as well?

IMO both statement 1 and 2 are insufficient becasue question ask about how many diffrent number. using both statement 1 and 2 still we can get infinite numbers of solution, hence answer should be E

S1 is not sufficient. Consider \(A = 0\) (the answer is 0) and \(A = 1\) (the answer is 1).

S2 is sufficient. Because \(A \gt 1\) , \(A \gt 0\) and the only \(y\) that satisfies the condition is \(\frac{C - B}{A}\) . The correct answer is B.

Is the explanation for statement 2 correct? Why couldn't y = 0 and some other number as well?

S1 says C>B, and the question says Ay + B = C, doesn't this mean A cannot be equal to 0, because if it was, then B = C (from Ay + B = C) and thus contradicting Statement 1.