Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

The center of the circle is at point \((0, 6)\) . If the distance between the two points where the circle intersects the x-axis is 16, what is the area of the circle?

The center of the circle is at point \((0, 6)\) . If the distance between the two points where the circle intersects the x-axis is 16, what is the area of the circle?

Can someone please explain this question stem with figure?

Below is a diagram:

Attachment:

Circle.png [ 11.15 KiB | Viewed 1945 times ]

As you can see the radius of the circle is a hypotenuse of a right triangle with the sides equal to 6 and 16/2=8 (6-8-10 right triangle), so radius=hypotenuse=10. The area is \(\pi{r^2}=100\pi\).

The center of the circle is at point (0, 6)[/m]. If the [#permalink]

Show Tags

13 Dec 2012, 02:01

The center of the circle is at point (0, 6). If the distance between the two points where the circle intersects the x-axis is 16, what is the area of the circle?

A. \(36\pi\) B. \(45\pi\) C. \(64\pi\) D. \(81\pi\) E. \(100\pi\)

Last edited by Bunuel on 13 Dec 2012, 02:05, edited 1 time in total.

The center of the circle is at point (0, 6). If the distance between the two points where the circle intersects the x-axis is 16, what is the area of the circle?

A. \(36\pi\) B. \(45\pi\) C. \(64\pi\) D. \(81\pi\) E. \(100\pi\)

Merging similar topics. Please refer to the solutions above.
_________________

The center of the circle is at point \((0, 6)\) . If the distance between the two points where the circle intersects the x-axis is 16, what is the area of the circle?

Can someone please explain this question stem with figure?

Below is a diagram:

Attachment:

Circle.png

As you can see the radius of the circle is a hypotenuse of a right triangle with the sides equal to 6 and 16/2=8 (6-8-10 right triangle), so radius=hypotenuse=10. The area is \(\pi{r^2}=100\pi\).

Answer: E.

Hope it helps.

M taking abt y intercept which is 16 and x intercept -4?How did u draw this ! I understood that it will cross 8 and -8 on both side of x axis.
_________________

Bole So Nehal.. Sat Siri Akal.. Waheguru ji help me to get 700+ score !

The center of the circle is at point \((0, 6)\) . If the distance between the two points where the circle intersects the x-axis is 16, what is the area of the circle?

Can someone please explain this question stem with figure?

Below is a diagram:

Attachment:

Circle.png

As you can see the radius of the circle is a hypotenuse of a right triangle with the sides equal to 6 and 16/2=8 (6-8-10 right triangle), so radius=hypotenuse=10. The area is \(\pi{r^2}=100\pi\).

Answer: E.

Hope it helps.

M taking abt y intercept which is 16 and x intercept -4?How did u draw this ! I understood that it will cross 8 and -8 on both side of x axis.

Sorry but do not follow you. What do you mean by "how did you draw it"?

If you understand that x intercepts are at -8 and 8, then you can get the radius as shown in my post. Drawing is just to illustrate.
_________________

Ohk Bunuel dear .. Finally I got that now.. hypotenuse is 10 so from 6 to -4 distance is 10 and from 6 to 16 distance is 10..Its clear now
_________________

Bole So Nehal.. Sat Siri Akal.. Waheguru ji help me to get 700+ score !

How will I understand without drawing that the two points are (0, -8) and (0, 8)? Why not (0, -7) and (0, 9)? Please make it clear.

The center of the circle is on y-axis, so it's symmetric around it. We know that the the distance between the two points where the circle intersects the x-axis is 16, hence half of it (8 units) must be to the left of 0 and the remaining half (another 8 units) to the right of 0.