nerd wrote:

10! is for sure divisible by 3

so 10!+ 20 will have 10!+3, 10!+6,10!+9,10!+12, 10!+15 & 10!+18 total 6 + 10! which is alreday divisible by 3

so 6+1 =7

10! is divisible by 3 as 10! = 2 * 3 *4 * 5* 6* 7* 8* 9* 10

The nearest and farthest multiple in the range, 10! and 10! +18

The difference between the extremes 10! + 18 – 10! = 18

So number of multiples in the range (18/3) + 1 = 7

Hence, option (B) is the answer.