Sorry , I don't know how to format it correctly here, so pasting the image.
My doubt is .. If we take 5 raised to 4 as common in the denominator,
we will be left with
[5 raised to 4 ( 5 raised to 3 - 1 ) ] raised to -2.
Now this can be deduced to
5 raised to 2 * [5 raised to 3 - 1 ] raised to -2 ..
So 25 remains in the denominator .
However , if we do not take 5 raised to 4 as common in the denominator, the entire denominator can be taken above in the numerator by changing the sign of the exponent to positive 2.
In this case no 25 remains in the denominator.
I don't understand where I am going wrong . Kindly help.
qs.JPG [ 18.05 KiB | Viewed 839 times ]
hope is a good thing, maybe the best of things. And no good thing ever dies.
Who says you need a 700 ?Check this out : http://gmatclub.com/forum/who-says-you-need-a-149706.html#p1201595
My GMAT Journey : end-of-my-gmat-journey-149328.html#p1197992