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# Machince A and B are each used to manufacture 660 sprockets.

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Machince A and B are each used to manufacture 660 sprockets. [#permalink]  08 Apr 2008, 23:45
Machince A and B are each used to manufacture 660 sprockets. It takes A 10 hours longer to produce 660 sprockets than machine B. B produces 10 percent more sprockets per hour than A. How many sprockets per hours does machine A produce?

A. 6
B. 6.6
C. 60
D. 100
E 110
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Re: Work Problem [#permalink]  09 Apr 2008, 00:09
I think the correct answer is A.

Machine A produces at a speed of A sp/hour and B at a speed of B sp/hour.
so, 660/A=(660/B)+10 and B=1,1 A--->1,1*660=660+11A--->A=6, so answer A is correct
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Re: Work Problem [#permalink]  09 Apr 2008, 08:43
Speed of A = \frac{660}{n + 10} sockets/hour

Speed of B = \frac{660}{n} sockets/hour

Speed of B = 10 % of Speed of A

--> \frac{660}{n} = 1.1*\frac{660}{n + 10} --> \frac{1}{n} = 1.1*\frac{1}{(n + 10)} --> {n+10} = 1.1*{n} ---> {n} = 100 ---> Hence speed of A = \frac {660}{110} = 6 sockets/hr
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Re: Work Problem [#permalink]  09 Apr 2008, 10:54

by testing those
and it is not take much time
and i think it is took less time than by equation
SVP
Joined: 04 May 2006
Posts: 1943
Schools: CBS, Kellogg
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Re: Work Problem [#permalink]  09 Apr 2008, 23:36
Thanks guys,
OA is A
Re: Work Problem   [#permalink] 09 Apr 2008, 23:36
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