Machine A and Machine B can produce 1 widget in 3 hours : Quant Question Archive [LOCKED]
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# Machine A and Machine B can produce 1 widget in 3 hours

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Machine A and Machine B can produce 1 widget in 3 hours [#permalink]

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18 May 2007, 16:44
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Machine A and Machine B can produce 1 widget in 3 hours working together at their respective constant rates. If Machine A's speed were doubled, the two machines could produce 1 widget in 2 hours working together at their respective rates. How many hours does it currently take Machine A to produce 1 widget on its own?

a) 1/2

b) 2

c) 3

d) 5

e) 6
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Re: Word Problem - machines [#permalink]

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18 May 2007, 19:26
above720 wrote:
Machine A and Machine B can produce 1 widget in 3 hours working together at their respective constant rates. If Machine A's speed were doubled, the two machines could produce 1 widget in 2 hours working together at their respective rates. How many hours does it currently take Machine A to produce 1 widget on its own?

a) 1/2

b) 2

c) 3

d) 5

e) 6

(E) it is

A = hours it takes machine A to produce 1 widget on its own
B = hours it takes machine B to produce 1 widget on its own

1/A + 1/B = 1/3
=> 3B + 3A = AB (1)

2/A + 1/B = 1/2
=> 4B + 2A = AB (2)

(1) & (2) => A = B

=> A = 6
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Re: Word Problem - machines [#permalink]

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18 May 2007, 20:29
above720 wrote:
Machine A and Machine B can produce 1 widget in 3 hours working together at their respective constant rates. If Machine A's speed were doubled, the two machines could produce 1 widget in 2 hours working together at their respective rates. How many hours does it currently take Machine A to produce 1 widget on its own?

a) 1/2

b) 2

c) 3

d) 5

e) 6

= inverse of (1/2 - 1/3) = inverse (1/6) = 6 hours.
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18 May 2007, 20:32
A+B = 1/3 => 3A + 3B = 1 => 6A + 6B = 2
2A+B = 1/2 => 4A + 2B = 1 => 12A + 6B = 3

Together, 6A = 1 => A = 1/6. So A takes 6 hours to produce the widget
18 May 2007, 20:32
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