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# machine A produces pencils at a constant rate of 9000

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Manager
Joined: 05 Jul 2006
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machine A produces pencils at a constant rate of 9000 [#permalink]  29 Sep 2006, 07:13
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machine A produces pencils at a constant rate of 9000 pencils per hour and machine B produces pencils at a constant rate of 7000 pencils per hour. If two machines together must produce pencils and if each machine can operate for at most 8 hours, what is the least amount of time, in hours, that machine B must operate?

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Senior Manager
Joined: 31 Jul 2006
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Re: PS-work [#permalink]  29 Sep 2006, 17:07
lan583 wrote:
machine A produces pencils at a constant rate of 9000 pencils per hour and machine B produces pencils at a constant rate of 7000 pencils per hour. If two machines together must produce pencils and if each machine can operate for at most 8 hours, what is the least amount of time, in hours, that machine B must operate?

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Is it me or are you missing total number of penciles?
Manager
Joined: 05 Jul 2006
Posts: 198
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Kudos [?]: 24 [0], given: 0

here is the correct question:

machine A produces pencils at a constant rate of 9000 pencils per hour and machine B produces pencils at a constant rate of 7000 pencils per hour. If two machines together must produce 100000 pencils and if each machine can operate for at most 8 hours, what is the least amount of time, in hours, that machine B must operate?
VP
Joined: 21 Aug 2006
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9000*8 hours + 7000*4hours =100000

Is it 4 hours Ian?
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Manager
Joined: 13 Sep 2006
Posts: 198
Schools: Olin Business School - Washington University
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Kudos [?]: 20 [0], given: 0

Straight A.

Machine A works 8 hours, producing 72k pencils, Machine B comes in to produce 28k. 28000/7000 = 4 hours.
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