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machine A produces pencils at a constant rate of 9000

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machine A produces pencils at a constant rate of 9000 [#permalink] New post 29 Sep 2006, 07:13
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machine A produces pencils at a constant rate of 9000 pencils per hour and machine B produces pencils at a constant rate of 7000 pencils per hour. If two machines together must produce pencils and if each machine can operate for at most 8 hours, what is the least amount of time, in hours, that machine B must operate?

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Re: PS-work [#permalink] New post 29 Sep 2006, 17:07
lan583 wrote:
machine A produces pencils at a constant rate of 9000 pencils per hour and machine B produces pencils at a constant rate of 7000 pencils per hour. If two machines together must produce pencils and if each machine can operate for at most 8 hours, what is the least amount of time, in hours, that machine B must operate?

4
4(2/3)
5(1/3)
6
6(1/4)


Is it me or are you missing total number of penciles?
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 [#permalink] New post 29 Sep 2006, 19:16
here is the correct question:

machine A produces pencils at a constant rate of 9000 pencils per hour and machine B produces pencils at a constant rate of 7000 pencils per hour. If two machines together must produce 100000 pencils and if each machine can operate for at most 8 hours, what is the least amount of time, in hours, that machine B must operate?
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 [#permalink] New post 29 Sep 2006, 22:36
9000*8 hours + 7000*4hours =100000

Is it 4 hours Ian?
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 [#permalink] New post 29 Sep 2006, 23:25
Straight A.

Machine A works 8 hours, producing 72k pencils, Machine B comes in to produce 28k. 28000/7000 = 4 hours.
  [#permalink] 29 Sep 2006, 23:25
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