machine X and Y run at different constant rates, and machine

Oldest

Best Reply

Author

Message

TAGS:

Manager

Joined: 30 Mar 2007

Posts: 183

Followers: 1

Kudos [?]: 0 [0], given: 0

machine X and Y run at different constant rates, and machine [#permalink]

01 Jun 2007, 12:25

machine X and Y run at different constant rates, and machine x can complete a certain job in 9 hours. machine X worked on the job alone for the first 3 hours and the two machines, working together, then completed the job in 4 more hours. How many hours would it have taken machine y working alone to complete the entire job?
Ａ）１８　Ｂ）１３ 1/2 C)7 1/5

Manager

Joined: 22 May 2007

Posts: 124

Followers: 1

Kudos [?]: 1 [0], given: 0

[#permalink]

01 Jun 2007, 12:40

I believe it is C.

1/9 + 1/x =1/4 --->>> x=24/5 so in 24/5 hours, the other machine completes 6/9 of the work.

24/5 divided by 6/9 gives us the answer of 36/5 or 7 1/5.

What is OA?

Manager

Joined: 22 May 2007

Posts: 124

Followers: 1

Kudos [?]: 1 [0], given: 0

[#permalink]

01 Jun 2007, 13:07

That's right! By backsolving I get 18 or A.

I got fooled, gotta work on these problems

))

Manager

Joined: 14 Mar 2007

Posts: 98

Followers: 1

Kudos [?]: 1 [0], given: 0

[#permalink]

01 Jun 2007, 13:36

A. 18

Mch X can do the job in 9 hours
in 1 hour = 1/9
Working alone for 3 hours = 3/9
So 1-3/9 = 6/9 of the job is left
Mch X and Mch Y do 6/9 in 4 hours

Now lets assume Mch Y will do the job in y hours
In 1 hour = 1/y

So both of them together in 1 hour
1/9+1/y = 9+y/9y

In 4 hours they do
4(9+y)/9y
This is equal to 6/9
Solve to get y = 18

Director

Joined: 12 Jun 2006

Posts: 544

Followers: 1

Kudos [?]: 6 [0], given: 1

Re: work question [#permalink]

01 Jun 2007, 17:09

Jamesk486 wrote:

I noticed that not all of the answer choices were listed. I think the answer is 12. If not, will someone tell me why we couldn't solve the prob this way:

x rate = 1/9, x works for 3 hrs and completes 1/3 of the work.

now, x and y wrapped up the remaining 2/3 of work in 4 hrs:
r(4)=2/3 ==> r = 2/3(1/4) = 2/12 = 1/6.

so, x's rate is 1/9 and x's and y's combined rate is 1/6. in order to find y's rate let's subtract 1/9 (x's rate) from 1/6 (x's and y's combined rate)

1/6 - 1/9 = 1/18. 1/18 is y's rate. the prob asks: How many hours would it have taken machine y working alone to complete the entire job? so, 1/18t=2/3 ==> t=36/3 = 12.

What do you all think? Any probs w/this?

Re: work question [#permalink] 01 Jun 2007, 17:09

		Similar topics	Author	Replies	Last post
Similar Topics:		Machine X and Y run at different constant rates. Machine X	ftoor	1	20 Dec 2003, 22:07
		Running at their respective constant rates, machine X takes	chunjuwu	3	22 Aug 2004, 03:18
		Running at their respective constant rates, machine X takes	falcor	2	17 Sep 2004, 12:43
		Running at their respective constant rates, machine X takes	LADodgers	2	06 Nov 2004, 00:42
	2	Machines X and Y run at different constant rates, and	Jamesk486	6	09 Jul 2008, 06:38

machine X and Y run at different constant rates, and machine

Main navigation

GMAT Resources

Partners

MBA Resources

GMAT ® is a registered trademark of the Graduate Management Admission Council ® (GMAC ®). GMAT Club's website has not been reviewed or endorsed by GMAC.

GMAT Courses

Admissions Consulting

machine X and Y run at different constant rates, and machine

machine X and Y run at different constant rates, and machine

Main navigation

GMAT Resources

Partners

MBA Resources