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Machines X and Y produced identical bottles at different

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Machines X and Y produced identical bottles at different [#permalink] New post 23 Oct 2006, 00:21
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Machines X and Y produced identical bottles at different constant rates. Machine X, operating alone for 4 hours, filled part of a production lot; then machine Y, operating alone fore 3 hours, filled the rest of this lot. How many hours would it have taken machine X operating alone to fill the entire production lot if machine X produced twice as many bottles in 4 hours as machine Y produced in 3 hours?

... I can't seem to set-up the equation for this.

... Also as a side question, is it worth it to buy access to the $75 GMATclub challenges? Does it come with explanations?
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 [#permalink] New post 23 Oct 2006, 04:38
say Machine X has speed of x unit/ hr
say Machine Y has speed of y unit/hr


X produce in 4 hrs = 4x unit
Y produce in 3 hrs = 3y unit

its given ,
X produce in 4 hrs = 2 (Y produce in 3 hrs)

4x = 2 * 3y
or 2x = 3 y ------(1)


Machine capacity = 4x + 3y = 4x + 2x = 6x ( using 1)

So machine X will take 6 hrs for entire production alone
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 [#permalink] New post 23 Oct 2006, 04:40
Lets see if that makes sense....

4x=d
3x=T-d

d- work done by X
T- Total work

From the question we know:

d=2(T-d)
d=2T-2d
d+2d=2T
3d=2T
T=(3/2)d

3x=(3/2*d)-d
3x=1/2d.... which means that Y did half of the job in 3 hours.....

And X did half job in 4 hours.... So working alone Machine X would do the job in 8 hours....

Answer 8 hours
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 [#permalink] New post 23 Oct 2006, 11:13
AK wrote:
say Machine X has speed of x unit/ hr
say Machine Y has speed of y unit/hr


X produce in 4 hrs = 4x unit
Y produce in 3 hrs = 3y unit

its given ,
X produce in 4 hrs = 2 (Y produce in 3 hrs)

4x = 2 * 3y
or 2x = 3 y ------(1)


Machine capacity = 4x + 3y = 4x + 2x = 6x ( using 1)

So machine X will take 6 hrs for entire production alone


Yeah... the use of 3x=T-d in my calculation is wrong, because you cannot assume the same work rates for both of the machines....

Your answer should be correct....
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 [#permalink] New post 24 Oct 2006, 05:48
Code:
Machines X and Y produced identical bottles at different constant rates. Machine X, operating alone for 4 hours, filled part of a production lot; then machine Y, operating alone fore 3 hours, filled the rest of this lot. How many hours would it have taken machine X operating alone to fill the entire production lot if machine X produced twice as many bottles in 4 hours as machine Y produced in 3 hours?


I think this can be solved without setting up the equation.

We know this
machine X produced twice as many bottles in 4 hours as machine Y produced in 3 hours..............(1)

We also know that
machine X filled the production lot for 4 hours.
AND machine Y filled the production lot for 3 hours. .......................(2)

So from (1) and (2),
Machine X filled 2/3 of the production lot (IN its 4 hours)

To fill the whole lot.......it takes 4*3/2 = 6 hours
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 [#permalink] New post 24 Oct 2006, 07:03
Girikorat... Don't understand how you got 2/3 from (1) and (2). And why you multiplied it by 4?

I think yours is a much simpler and quicker way of solving so trying to understand and pick-up on your logic method. Hope you can explain. thanks :)
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 [#permalink] New post 24 Oct 2006, 11:42
Let T be the total number of bottles required to fill the parking lot.
In 4 hours let X prodcuce a bottles
then in 3 hours y produce T-X bottles.

As per the given condition

x=2(T-x) thus 3x=2t..t=3x/2

For x

4 hrs..... x bottles
Y........... 3x/2

thus Y =4*(3x)/(2x)=6hrs

Thus answer is 6 hours.

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 [#permalink] New post 25 Oct 2006, 01:29
Lets say mc Y produced N bottles in 3 hours.

Then according to que - mc X produced 2N bottles in 4 hours.

Also given in the que is total production lot comprises 4 hrs worth of mc X work and 3 hours worth of Mc Y work.

So total lot = N + 2N = 3N.

Mc X produces 2N in 4 hours. It'll produce another N in 2 hours working at constant rate.

So total time taken by X to fill the lot is 4 + 2 = 6 hours.
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 [#permalink] New post 26 Oct 2006, 04:33
dwivedys, you brought enlightenment again!!!

i like how you think the problems thru... thanks man
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