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Machines X and Y produced identical bottles at different

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Director
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Machines X and Y produced identical bottles at different [#permalink] New post 05 Jan 2004, 19:50
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A
B
C
D
E

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Machines X and Y produced identical bottles at different constant rates. Machine X, operating alone for 4 hours, filled part of a production lot; then machine Y, operating alone for 3 hours, filled the rest of this lot. How many hours would it have taken machine X operating alone to fill the entire production lot?

(1) Machine X produced 30 bottles per minute.
(2) Machine X produced twice as many bottles in 4 hours as machine Y produced in 3 hours.

show your work..pls
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 [#permalink] New post 05 Jan 2004, 20:06
Machines X and Y produced identical bottles at different constant rates. Machine X, operating alone for 4 hours, filled part of a production lot; then machine Y, operating alone for 3 hours, filled the rest of this lot. How many hours would it have taken machine X operating alone to fill the entire production lot?

(1) Machine X produced 30 bottles per minute.
(2) Machine X produced twice as many bottles in 4 hours as machine Y produced in 3 hours.

show your work..pls

--------------------------------------------------------------------------------
SOLN:

X = x bottles/hr
Y = y bottles/hr

4x + 3y = full container = Ax , A number of hrs to fill the container ---- I

1 - tells me nothing about relation between X & Y
2 - tells me
4x = 2*3y = 6y => 3y = 2x, fill this into the equation I
4x + 2x = 6x, 6 hrs

Hence 2 alone is the answer, 1 is useless information, actually it is extra info.
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 [#permalink] New post 05 Jan 2004, 20:08
I got c)

we need to know the entire production lot and the rates of each machine.

1) Insuffeesh

2) Insuffeesh


1) tells us machine X produced 4800 bottles in its shift nothing about the entire production lot.

2) Work = Rate x Time

Tells us machine X produced twice as many bottles as machine Y. Thus, Wx = 2Wy

Thus Rx X 4= 2 (Ry X 3) = Rx/Ry = 3

Having both we would know Ry's Rate
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 [#permalink] New post 05 Jan 2004, 20:10
I fell off the wagon on this. I agree it's B.
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 [#permalink] New post 05 Jan 2004, 20:16
Titleist wrote:
I fell off the wagon on this. I agree it's B.


gotcha..yeh, It's B
I must be under the influence of some other bottle :drunk

thanks!
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 [#permalink] New post 05 Jan 2004, 20:19
maybe 1 more problem then I'll go watch the season premier of curb your enthusiasm on VOD. :lol:
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 [#permalink] New post 05 Jan 2004, 20:22
Titleist wrote:
maybe 1 more problem then I'll go watch the season premier of curb your enthusiasm on VOD. :lol:


here u go..easy one:

For any numbers a and b, a ┬╖ b = a + b тАУ ab. If a ┬╖ b = 0, which of the following CANNOT be a value of b?
(A) 2
(B) 1
(C) 0
(D) -1
(E) -3/2
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 [#permalink] New post 05 Jan 2004, 20:41
Oh dj - I just came back from the fridge. What did you leave here for me??? A function proble :? m???
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 [#permalink] New post 05 Jan 2004, 20:44
dj wrote:
Titleist wrote:
maybe 1 more problem then I'll go watch the season premier of curb your enthusiasm on VOD. :lol:


here u go..easy one:

For any numbers a and b, a ┬╖ b = a + b тАУ ab. If a ┬╖ b = 0, which of the following CANNOT be a value of b?
(A) 2
(B) 1
(C) 0
(D) -1
(E) -3/2


Let's see,

a @ b = 0 and a + b - ab

thus, a + b(1-a)=0

if I choose 1 as b, then

a+ 1(1-a)=0, thus 1=0

c? can I go watch tv???
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 [#permalink] New post 05 Jan 2004, 20:52
titleist, you were to the point, but missed in picking up the right answer.

as you showed 1=0 when b=1, which is not possible. Hence, the answer

B
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 [#permalink] New post 05 Jan 2004, 20:54
dj wrote:
titleist, you were to the point, but missed in picking up the right answer.

as you showed 1=0 when b=1, which is not possible. Hence, the answer

B


thanks I will drink my beer and watch my show now! hahaha. Good night!
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 [#permalink] New post 05 Jan 2004, 20:55
Dj, that's the second time tonight that I got the answer right and the question choice wrong. Case and point - no more GMAT problems for me tonight! Buenos Nachos!
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 [#permalink] New post 09 Jan 2004, 22:34
Let n be number of bottles produced by X and n by Y
m+n = total number of bottles
since m = 2n n = m/2
The machine X working alone should finish m/2 additional bottles
for m it takes 4 hours for m/2 it will take 2 hours
so 6 hours are needed.

B is sufficient
  [#permalink] 09 Jan 2004, 22:34
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