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VP
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Machines X and Y produced identical bottles at different [#permalink]
05 Jan 2004, 20:50
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Machines X and Y produced identical bottles at different constant rates. Machine X, operating alone for 4 hours, filled part of a production lot; then machine Y, operating alone for 3 hours, filled the rest of this lot. How many hours would it have taken machine X operating alone to fill the entire production lot?
(1) Machine X produced 30 bottles per minute.
(2) Machine X produced twice as many bottles in 4 hours as machine Y produced in 3 hours.
show your work..pls
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Intern
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Machines X and Y produced identical bottles at different constant rates. Machine X, operating alone for 4 hours, filled part of a production lot; then machine Y, operating alone for 3 hours, filled the rest of this lot. How many hours would it have taken machine X operating alone to fill the entire production lot?
(1) Machine X produced 30 bottles per minute.
(2) Machine X produced twice as many bottles in 4 hours as machine Y produced in 3 hours.
show your work..pls
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SOLN:
X = x bottles/hr
Y = y bottles/hr
4x + 3y = full container = Ax , A number of hrs to fill the container ---- I
1 - tells me nothing about relation between X & Y
2 - tells me
4x = 2*3y = 6y => 3y = 2x, fill this into the equation I
4x + 2x = 6x, 6 hrs
Hence 2 alone is the answer, 1 is useless information, actually it is extra info.
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Director
Joined: 14 Oct 2003
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I got c)
we need to know the entire production lot and the rates of each machine.
1) Insuffeesh
2) Insuffeesh
1) tells us machine X produced 4800 bottles in its shift nothing about the entire production lot.
2) Work = Rate x Time
Tells us machine X produced twice as many bottles as machine Y. Thus, Wx = 2Wy
Thus Rx X 4= 2 (Ry X 3) = Rx/Ry = 3
Having both we would know Ry's Rate
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Director
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I fell off the wagon on this. I agree it's B.
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VP
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Titleist wrote: I fell off the wagon on this. I agree it's B.
gotcha..yeh, It's B
I must be under the influence of some other bottle
thanks!
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Director
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maybe 1 more problem then I'll go watch the season premier of curb your enthusiasm on VOD.
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VP
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Titleist wrote: maybe 1 more problem then I'll go watch the season premier of curb your enthusiasm on VOD. 
here u go..easy one:
For any numbers a and b, a ┬╖ b = a + b тАУ ab. If a ┬╖ b = 0, which of the following CANNOT be a value of b?
(A) 2
(B) 1
(C) 0
(D) -1
(E) -3/2
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Director
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Oh dj - I just came back from the fridge. What did you leave here for me??? A function proble  m???
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Director
Joined: 14 Oct 2003
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dj wrote: Titleist wrote: maybe 1 more problem then I'll go watch the season premier of curb your enthusiasm on VOD.  here u go..easy one: For any numbers a and b, a ┬╖ b = a + b тАУ ab. If a ┬╖ b = 0, which of the following CANNOT be a value of b? (A) 2 (B) 1 (C) 0 (D) -1 (E) -3/2
Let's see,
a @ b = 0 and a + b - ab
thus, a + b(1-a)=0
if I choose 1 as b, then
a+ 1(1-a)=0, thus 1=0
c? can I go watch tv???
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VP
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titleist, you were to the point, but missed in picking up the right answer.
as you showed 1=0 when b=1, which is not possible. Hence, the answer
B
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Director
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dj wrote: titleist, you were to the point, but missed in picking up the right answer.
as you showed 1=0 when b=1, which is not possible. Hence, the answer
B
thanks I will drink my beer and watch my show now! hahaha. Good night!
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Director
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Dj, that's the second time tonight that I got the answer right and the question choice wrong. Case and point - no more GMAT problems for me tonight! Buenos Nachos!
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SVP
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Let n be number of bottles produced by X and n by Y
m+n = total number of bottles
since m = 2n n = m/2
The machine X working alone should finish m/2 additional bottles
for m it takes 4 hours for m/2 it will take 2 hours
so 6 hours are needed.
B is sufficient
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