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# Machines X and Y work at their respective constant rates.

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Manager
Joined: 24 Apr 2008
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Machines X and Y work at their respective constant rates. [#permalink]

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04 May 2008, 17:09
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Machines X and Y work at their respective constant rates. How many more hours
does it take machine Y, working alone, to fill a production order of a certain
size than it takes machine X, working alone?

i) Machines X and Y, working together, fill a production order of this size in
2/3 the time that machine X, working alone, does.

ii) Machine Y, working alone, fills a production order of this size in twice the
time that machine X, working alone, does.
VP
Joined: 10 Jun 2007
Posts: 1459
Followers: 7

Kudos [?]: 207 [1] , given: 0

Re: DS - machine rate [#permalink]

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04 May 2008, 17:34
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quiet888 wrote:
Machines X and Y work at their respective constant rates. How many more hours
does it take machine Y, working alone, to fill a production order of a certain
size than it takes machine X, working alone?

i) Machines X and Y, working together, fill a production order of this size in
2/3 the time that machine X, working alone, does.

ii) Machine Y, working alone, fills a production order of this size in twice the
time that machine X, working alone, does.

E

x = time Y to complete the job alone
t = time X to complete the job alone
We are looking for x-t = ?

(1) We can say
1/x + 1/t = 3/(2t)
Solve for x, you get x=2t
Therefore x-t = t
INSUFFICIENT as we need to know t

(2) Same information given as (1).
INSUFFICIENT as we need to know t

Together, same. We need to know t in order to compute x-t
Re: DS - machine rate   [#permalink] 04 May 2008, 17:34
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