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# Marc can buy a certain computer for p1 dollars in State A,

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Manager
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Marc can buy a certain computer for p1 dollars in State A, [#permalink]

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12 Dec 2005, 05:25
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Marc can buy a certain computer for p1 dollars in State A, where the sales tax is t1 percent, or he can buy the same computer for p2 dollars in State B, where the sales tax is t2 percent. Is the total cost of the computer greater in State A than in State B?
(1) t1 > t2
(2) p1t1 > p2t2

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
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Re: DS - Total costs - Sounds easy [#permalink]

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12 Dec 2005, 06:24
TOUGH GUY wrote:
Marc can buy a certain computer for p1 dollars in State A, where the sales tax is t1 percent, or he can buy the same computer for p2 dollars in State B, where the sales tax is t2 percent. Is the total cost of the computer greater in State A than in State B?
(1) t1 > t2
(2) p1t1 > p2t2

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

My vote for E
1)t1>t2 but what if P1<P2 for examle P1=200 t1=20
P2=100 t1=10
There can be a lot of numbers for t1 t2 or p1 or p2 Insuff
2On the first look it seems to be suff , but..IMHO From statement 2 we just can figure out the amount of price1*on tax percent 1>than price2*tax percent2
While we need Price1+price1*tax percent1>or<Price2+price2*tax2
together same!
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13 Dec 2005, 07:49
We need to prove that p1 + p1t1 > p2 + p2t2

If p1t1 > p2t2

And if t1> t2

Than p1>p2 and p1 + p1t1 > p2 + p2t2

I will go for C than
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13 Dec 2005, 08:02
TOUGH GUY wrote:
We need to prove that p1 + p1t1 > p2 + p2t2

If p1t1 > p2t2

And if t1> t2

Than p1>p2 and p1 + p1t1 > p2 + p2t2

I will go for C than

How are you inferring that p1>p2?
CEO
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Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
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14 Dec 2005, 16:59
TOUGH GUY wrote:
We need to prove that p1 + p1t1 > p2 + p2t2

If p1t1 > p2t2

And if t1> t2

Than p1>p2 and p1 + p1t1 > p2 + p2t2

I will go for C than

How are you inferring that p1>p2?

Must be E.

p1>p2 can not be inferred. Example

P1 = 4, T1 = 6
P2 = 5, T2 = 4

Here 6 > 4 (T1 > T2) and 24 > 20 (P1T1 > P2T2) still P1 < P2 (4 < 5)

Am I right guys?
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Manager
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14 Dec 2005, 18:14
ps_dahiya wrote:
TOUGH GUY wrote:
We need to prove that p1 + p1t1 > p2 + p2t2

If p1t1 > p2t2

And if t1> t2

Than p1>p2 and p1 + p1t1 > p2 + p2t2

I will go for C than

How are you inferring that p1>p2?

Must be E.

p1>p2 can not be inferred. Example

P1 = 4, T1 = 6
P2 = 5, T2 = 4

Here 6 > 4 (T1 > T2) and 24 > 20 (P1T1 > P2T2) still P1 < P2 (4 < 5)

Am I right guys?

I agree with you. I wasn't quite sure how the other poster could infer that p1>p2. I think its E
14 Dec 2005, 18:14
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