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Margie and Maggie can finish the job together in 3 hours. If

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Margie and Maggie can finish the job together in 3 hours. If [#permalink] New post 12 Jun 2004, 15:23
Margie and Maggie can finish the job together in 3 hours. If Margie can do the job by herself in 5 hours, what percent of the job does Maggie do?
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 [#permalink] New post 12 Jun 2004, 16:37
maggine in an hour = 1/3-1/5=2/15

magge/marie = (2/15/)(1/5) = 2/3

maggie does 33.3% of the job
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 [#permalink] New post 12 Jun 2004, 19:52
Margie does 3/5th of the job and Maggie does 2/5th of the job in 3 hours
So Maggie does 40% of the job.
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 [#permalink] New post 12 Jun 2004, 23:39
Anand is correct. Question was percent of the whole job,not compared to each other's job.I should be careful with the question, on what exactly is asked. adding to my error list.
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 [#permalink] New post 12 Jun 2004, 23:41
Anand is correct. Question was percent of the whole job,not compared to each other's job.I should be careful with the question, on what exactly is asked for.
Adding it to my error list.
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Re: common good [#permalink] New post 13 Jun 2004, 02:42
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lastochka wrote:
Margie and Maggie can finish the job together in 3 hours. If Margie can do the job by herself in 5 hours, what percent of the job does Maggie do?


If Margie's productivity is Mr, Maggie's productivity is Mg, then 3(Mr + Mg) = V = 5(Mr). => 2Mr = 3Mg => Maggie's productivity is equal to 2/3*Mr => she does 40%.
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 [#permalink] New post 18 Jun 2004, 01:59
margie does1/5 th in one hr and both of them work for three hrs and so margie does 1/5 * 3 = 3/5 of the work ,
magie=3/5 - 1 = 2/5
=40%

hope that helps

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  [#permalink] 18 Jun 2004, 01:59
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Margie and Maggie can finish the job together in 3 hours. If

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