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Martha bought several pencils. If each pencil was either a

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Martha bought several pencils. If each pencil was either a [#permalink] New post 27 Jun 2008, 18:31
Martha bought several pencils. If each pencil was either a 23-cent pencil or a 21-cent pencil, how many 23-cent pencil did martha buy?

(1). Marth bought a total of 6 pencils
(2). The total value of the pencils Marth bought was 130 cents.

state 1
x + y = 6 - insufficient

.23(x) + .21(y) = 1.30 cents

We could very well choose C but the actual answer could be found just using plug in in B.

I choose B, wait for you to concur. Thanks
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Re: Pencils [#permalink] New post 27 Jun 2008, 22:01
I'd go for B as well:

From the stem: .23 (x) + .21 (__-x) = $___

Statement 1:
.23 (x) + .21 (6-x) = $___
INSUFF

Statement 2:
Total numner of pencils must be 6, because 1.30/.21<7 and 1.30/.23>5
Therefore:
.23 (x) + .21 (6-x) = $1.30





Martha bought several pencils. If each pencil was either a 23-cent pencil or a 21-cent pencil, how many 23-cent pencil did martha buy?

(1). Marth bought a total of 6 pencils
(2). The total value of the pencils Marth bought was 130 cents.
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Re: Pencils [#permalink] New post 27 Jun 2008, 22:32
alimad wrote:
Martha bought several pencils. If each pencil was either a 23-cent pencil or a 21-cent pencil, how many 23-cent pencil did martha buy?

(1). Marth bought a total of 6 pencils
(2). The total value of the pencils Marth bought was 130 cents.

state 1
x + y = 6 - insufficient

.23(x) + .21(y) = 1.30 cents

We could very well choose C but the actual answer could be found just using plug in in B.

I choose B, wait for you to concur. Thanks


I will go for C, we have 2 unknowns so need to different equations
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Re: Pencils [#permalink] New post 28 Jun 2008, 02:17
Martha bought several pencils. If each pencil was either a 23-cent pencil or a 21-cent pencil, how many 23-cent pencil did martha buy?

(1). Marth bought a total of 6 pencils
(2). The total value of the pencils Marth bought was 130 cents.

*********
Statement 1 - x+y =6 is insufficient.

*********
Statement 2 -

0.23(x) + 0.21(y) = 1.30 cents

0.23x+0.21(6-x)=1.3

0.23+1.26-0.21x = 1.3

0.02x +1.26 = 1.3

0.02x =0.04

x = 0.04/0.02 = 2

Then test the original equation:
0.23 * 2 +0.21(y)=1.3

0.46 + 0.21 y = 1.3

0.21y = 1.3-0.46

0.21 y = 0.84

y = 4

This makes x+ y as six with worth 1.3 cents, which makes the the as perfect answer.
Re: Pencils   [#permalink] 28 Jun 2008, 02:17
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