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Martha- coops

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Martha- coops [#permalink] New post 11 Dec 2007, 10:27
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Martha takes a road trip from point A to point B. She drives x percent of the distance at 60 miles per hour and the remainder at 50 miles per hour. If Martha's average speed for the entire trip is represented as a fraction in its reduced form, in terms of x, which of the following is the numerator?

(A) 110
(B) 300
(C) 1,100
(D) 3,000
(E) 30,000
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Re: Martha- coops [#permalink] New post 11 Dec 2007, 11:40
Cooper2248817 wrote:
Martha takes a road trip from point A to point B. She drives x percent of the distance at 60 miles per hour and the remainder at 50 miles per hour. If Martha's average speed for the entire trip is represented as a fraction in its reduced form, in terms of x, which of the following is the numerator?

(A) 110
(B) 300
(C) 1,100
(D) 3,000
(E) 30,000


Ans. = E

average rate = d/t

t = [ (x/100)*d/60 + (1- x/100)*d/50]
= [ x/6000 + (100-x)/5000]*d
The least common denominator of t is 30,000.

Thus, average rate = d/t has the numerator of 30,000 as the reduced number since 30,000 is the least common denominator of t.
Re: Martha- coops   [#permalink] 11 Dec 2007, 11:40
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Martha- coops

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