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Mary has 11 more nickels ($0.05) than quarters ($0.25). How

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Mary has 11 more nickels ($0.05) than quarters ($0.25). How [#permalink] New post 11 Mar 2008, 11:17
Mary has 11 more nickels ($0.05) than quarters ($0.25). How many coins does
she have if the total value of her coins is $2.65?

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Re: gprep algebra [#permalink] New post 11 Mar 2008, 16:21
Suppose Mary has X quarters, then she has X + 11 nickels.
Total nickels and quarters should add upto 2.65.
So (X+11)*0.05 + X*0.25 = 2.65
=> 0.30X = 2.65 - 0.55
=> X = 7 (Number of Quarters)
Number of Nickels = 7+11 = 18

Total coins = 18+7 = 25

I do not see this option in Answer.
May be question asked for number of nickels Mary has, so in that case answer is 18.

Answer B.
Re: gprep algebra   [#permalink] 11 Mar 2008, 16:21
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Mary has 11 more nickels ($0.05) than quarters ($0.25). How

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