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Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]

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12 Dec 2012, 09:51

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Mary's income is 60 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income?

Re: Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]

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12 Dec 2012, 09:58

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Expert's post

Walkabout wrote:

Mary's income is 60 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income?

(A) 124% (B) 120% (C) 96% (D) 80% (E) 64%

Juan's income = 100 (assume); Tim's income = 60 (40 percent less than Juan's income); Mary's income = 96 (60 percent more than Tim's income).

Thus, Mary's income (96) is 96% of Juan's income (100).

Re: Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]

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02 Jul 2013, 23:19

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hfbamafan wrote:

Mary's income is 60 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income?

(A) 124% (B) 120% (C) 96% (D) 80% (E) 64%

I am working on trying to nail down these questions.

Is there a way to solve this problem by assuming that Mary's income is 160, which is 60% more than Juan's?

Or does that just cause problems.

Thanks, Hunter

You can do this way, though the way proposed in my post is better:

Mary's income = 160. Tim's income = 100; Juan's income = 100/0.6 = 500/3.

Re: Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]

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02 Jul 2013, 23:25

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If Tim's income is 100 and Marys income is 160 Juan's income, J, can be found by dividing Tim's income by .6 100 = .6J J = 167

Mary's income as a percentage of Juan's is then 160/167 = .96 (you can just estimate the .96 by looking at the answer choices) (also Mr. Bunuels method is way better) _________________

Re: Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]

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13 Apr 2014, 14:21

Mary's income is 60 percent more than Tim's income: M = 1.6T Tim's income is 40 percent less than Juan's income: T = 0.6J To compare them, we will need to rationalise the ratio of the 3 individuals M : T : J

M : T : J => 1 : 1.6(1) : 0.6(1.6) = 1 : 1.6 : 0.96

Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]

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07 Dec 2014, 23:56

Bunuel wrote:

Walkabout wrote:

Mary's income is 60 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income?

(A) 124% (B) 120% (C) 96% (D) 80% (E) 64%

Juan's income = 100 (assume); Tim's income = 60 (40 percent less than Juan's income); Mary's income = 96 (60 percent more than Tim's income).

Thus, Mary's income (96) is 96% of Juan's income (100).

Answer: C.

Hi Bunuel! Really hoping you can help me understand something. I can not for the life of me make this equation work by setting Tim 100. I read your other comment regarding this, but I saw you wrote: Mary's income = "100/0.6". May I ask why you divided 0.6 rather than multiplied?

My quant is very weak so sorry if the answer is obvious.

EDIT: I just ran into another question and made a similar mistake. Therefore I think my question needs to be when should I use "amount*0.%" vs "amount/1.%"?

E.g why did you (and others here) go with "100/0.6" and not "100*0.60" since it says Tim's income is 60% of Juan's;

Re: Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]

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31 Jan 2016, 11:43

Given: M = 1.6 T = 8/5T; [how did i get 8/5? 60% = 3/5 & 160% = 1+(3/5) = 8/5] T = 0.6J = 3/5J; Substitute T: M = 8/5 * (3/5)J M = 24/25J; You can either calculate 24/25 (I wouldn't) or know that 24/25 is little less than 1 ~= 0.96 (the only answer choice which is little less than 1) Hence, M = 0.96J or 96%J

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