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Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]
12 Dec 2012, 08:51

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Difficulty:

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Question Stats:

79% (02:31) correct
21% (01:54) wrong based on 456 sessions

Mary's income is 60 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income?

Re: Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]
12 Dec 2012, 08:58

Expert's post

Walkabout wrote:

Mary's income is 60 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income?

(A) 124% (B) 120% (C) 96% (D) 80% (E) 64%

Juan's income = 100 (assume); Tim's income = 60 (40 percent less than Juan's income); Mary's income = 96 (60 percent more than Tim's income).

Thus, Mary's income (96) is 96% of Juan's income (100).

Re: Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]
02 Jul 2013, 22:19

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Expert's post

1

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hfbamafan wrote:

Mary's income is 60 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income?

(A) 124% (B) 120% (C) 96% (D) 80% (E) 64%

I am working on trying to nail down these questions.

Is there a way to solve this problem by assuming that Mary's income is 160, which is 60% more than Juan's?

Or does that just cause problems.

Thanks, Hunter

You can do this way, though the way proposed in my post is better:

Mary's income = 160. Tim's income = 100; Juan's income = 100/0.6 = 500/3.

Re: Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]
02 Jul 2013, 22:25

1

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If Tim's income is 100 and Marys income is 160 Juan's income, J, can be found by dividing Tim's income by .6 100 = .6J J = 167

Mary's income as a percentage of Juan's is then 160/167 = .96 (you can just estimate the .96 by looking at the answer choices) (also Mr. Bunuels method is way better) _________________

Re: Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]
13 Apr 2014, 13:21

Mary's income is 60 percent more than Tim's income: M = 1.6T Tim's income is 40 percent less than Juan's income: T = 0.6J To compare them, we will need to rationalise the ratio of the 3 individuals M : T : J

M : T : J => 1 : 1.6(1) : 0.6(1.6) = 1 : 1.6 : 0.96

Mary's income is 60 percent more than Tim's income, and Tim' [#permalink]
07 Dec 2014, 22:56

Bunuel wrote:

Walkabout wrote:

Mary's income is 60 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income?

(A) 124% (B) 120% (C) 96% (D) 80% (E) 64%

Juan's income = 100 (assume); Tim's income = 60 (40 percent less than Juan's income); Mary's income = 96 (60 percent more than Tim's income).

Thus, Mary's income (96) is 96% of Juan's income (100).

Answer: C.

Hi Bunuel! Really hoping you can help me understand something. I can not for the life of me make this equation work by setting Tim 100. I read your other comment regarding this, but I saw you wrote: Mary's income = "100/0.6". May I ask why you divided 0.6 rather than multiplied?

My quant is very weak so sorry if the answer is obvious.

EDIT: I just ran into another question and made a similar mistake. Therefore I think my question needs to be when should I use "amount*0.%" vs "amount/1.%"?

E.g why did you (and others here) go with "100/0.6" and not "100*0.60" since it says Tim's income is 60% of Juan's;

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