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Material A costs $3 per kilogram, and material B costs $5 [#permalink]
13 Aug 2009, 14:55

00:00

A

B

C

D

E

Difficulty:

45% (medium)

Question Stats:

54% (01:00) correct
45% (01:39) wrong based on 94 sessions

Material A costs $3 per kilogram, and material B costs $5 per kilogram. If 10 kilograms of material K consists of x kilograms of material A and y kilograms of material B, is x > y?

(1) y > 4 (2) The cost of the 10 kilograms of material K is less than $40.

Re: Material A costs $3 per kilogram, and material B costs $5 pe [#permalink]
13 Aug 2009, 15:10

tejal777 wrote:

Material A costs $3 per kilogram, and material B costs $5 per kilogram. If 10 kilograms of material K consists of x kilograms of material A and y kilograms of material B, is x > y? (1) y > 4 (2) The cost of the 10 kilograms of material K is less than $40.

umm...(D) is it??

Yeah...its D.

St1: if y>4, then x =< 5 => x =< y => SUFFICIENT

St2: If 10 kg of material k cost $40, then x = y = 5 But if it costs less than $40 then y < 5 => x > 5 => SUFFICIENT

Re: Material A costs $3 per kilogram, and material B costs $5 pe [#permalink]
13 Aug 2009, 20:49

What if x = 4.9 kgs and y = 4.1 kgs? How do you know that material k consists materials A and B only in whole kgs?

B is not a big deal.

samrus98 wrote:

tejal777 wrote:

Material A costs $3 per kilogram, and material B costs $5 per kilogram. If 10 kilograms of material K consists of x kilograms of material A and y kilograms of material B, is x > y? (1) y > 4 (2) The cost of the 10 kilograms of material K is less than $40.

umm...(D) is it??

Yeah...its D.

St1: if y>4, then x =< 5 => x =< y => SUFFICIENT

St2: If 10 kg of material k cost $40, then x = y = 5 But if it costs less than $40 then y < 5 => x > 5 => SUFFICIENT

Re: Material A costs $3 per kilogram, and material B costs $5 pe [#permalink]
14 Aug 2009, 03:14

1

This post received KUDOS

yezz wrote:

samrus98 wrote:

tejal777 wrote:

Material A costs $3 per kilogram, and material B costs $5 per kilogram. If 10 kilograms of material K consists of x kilograms of material A and y kilograms of material B, is x > y? (1) y > 4 (2) The cost of the 10 kilograms of material K is less than $40.

umm...(D) is it??

Yeah...its D.

St1: if y>4, then x =< 5 => x =< y => SUFFICIENT

St2: If 10 kg of material k cost $40, then x = y = 5 But if it costs less than $40 then y < 5 => x > 5 => SUFFICIENT

ANS: D

Can you plz explain why we are excluding non intiger values for x,y? thanks

Its a mistake.

X & Y can take non-integer values as well and that makes St1 insufficient. Revised ANS: B _________________

Re: Material A costs $3 per kilogram, and material B costs $5 pe [#permalink]
17 Sep 2009, 10:13

B. couple of examples: x=4, y=6, sum>40. not satisfies x=5, y=5, sum =40. not satisfies x=6, y=4, sum<40. satisfies non-integers should be taken into account as well. However, they all satisfy this.
_________________

Re: Material A costs $3 per kilogram, and material B costs $5 pe [#permalink]
24 Sep 2009, 08:51

tejal777 wrote:

Material A costs $3 per kilogram, and material B costs $5 per kilogram. If 10 kilograms of material K consists of x kilograms of material A and y kilograms of material B, is x > y? (1) y > 4 (2) The cost of the 10 kilograms of material K is less than $40.

umm...(D) is it??

Hi,

From the stem we have: X (MAT A) + Y (MAT B) =10 (i) and 3X+5Y=TOTAL COST. (II)

FOR (1): Y>4. Y=4,1 and X=5,9 OR Y=6 and X=4 (INSUFFI)

FOR (2): 3X+5Y<40 ; 40*(I) => 40X+40Y=40 ; We have that 3x+5y< 40X+40Y => -37x<35y; Again (X+Y=10)=> X=6,Y=4 or X=4,Y=6 We dont know really. (INSUFFI)

FOR (1) and (2) => The same, we dont any more information! FOR THIS, IMO (E)

Re: Material A costs $3 per kilogram, and material B costs $5 pe [#permalink]
19 Oct 2009, 23:57

Came back to the question again:(

Quote:

Material A costs $3 per kilogram, and material B costs $5 per kilogram. If 10 kilograms of material K consists of x kilograms of material A and y kilograms of material B, is x > y? (1) y > 4 (2) The cost of the 10 kilograms of material K is less than $40.

OE says: Since x + y = 10, the relation x > y is equivalent to x > 10 – x, or x > 5. (1) The given information is consistent with x = 5.5 and y = 4.5, and the given information is also consistent with x = y = 5. Therefore, it is possible for x > y to be true and it is possible for x > y to be false; NOT sufficient.

How can we take the case of x = y = 5 when we know x>5??
_________________